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Mama L [17]
3 years ago
11

Helppppppppppppppp me plzzzzzzz

Mathematics
1 answer:
NeX [460]3 years ago
8 0

Answer:

B = j + H

Step-by-step explanation:

Given:

j = - H + B

Solve the equation for B

j = - H + B

Add H to both sides of the equation

j + H = - H + B + H

j + H = B

B = j + H

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please help me it is URGENT pls the first one is solve and the 2nd one is simplify I will give u lots of points thank you
klasskru [66]
I.) (5x+3)/4-(2x-4)/3=5
Clear fractions:
3·((5x+3)/4)=15x+9
4·((2x-4)/3)=8x-16
15x+9-(8x-16)=5
15x+9-8x+16=5
Combine like terms:
7x+25=5
7x=-20
x=-20/7

II.) (3/11)·(5/6)-(9/12)·(4/3)+(5/13)·(6/15)
Remember PEMDAS
So first multiply:
3/11·5/6=15/66
9/12·4/3=3/3·1/1=3/3=1
5/13·6/15=1/13·6/3=6/39=2/13
(15/66)-1+(2/13)
Combine:
15/66-1/1=15/66-66/66=-51/66
-51/66+2/3=-51/66+44/66=-7/66
Answer: -7/66 :)
7 0
4 years ago
Read 2 more answers
Chase and Alonzo stand next to each other and throw baseballs in the air.
PSYCHO15rus [73]

Answer:if you are solving for y

Step-by-step explanation:-4×2+5x+7

y=5x-1...

3 0
3 years ago
Read 2 more answers
Find a2 and a3 for the geometric sequence 4, a2, a3, 108.
LekaFEV [45]

9514 1404 393

Answer:

  a2 = 12

  a3 = 36

Step-by-step explanation:

Terms of a geometric sequence have a common ratio. If we call that ratio r, then we have ...

  a2 = 4r

  a3 = (a2)r = 4r^2

  108 = (a3)r = 4r^3

  27 = r^3 . . . . . . . . . . . divide by 4

  3 = r . . . . . . . . . . cube root

__

  a2 = 4(3) = 12

  a3 = 12(3) = 36

3 0
3 years ago
Jim saw that other bank offered the same rates but compounded the interest more often. Consider if he still put $15,000 into a s
Kazeer [188]

Compound interest is the addition of interest on the interest of the principal amount.

<h3>What is compound interest?</h3>

Compound interest is the addition of interest on the interest of the principal amount. It is given by the formula,

A = P(1+ \dfrac{r}{n})^{nt}

As it is given that the principal amount is $15,000; while the rate of interest is 2.8%, and the amount is invested for a period of 5 years.

A.) When the interest is charged weekly,

As we know that there are 52 weeks in a year, therefore, n = 52, substitute the values,

A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{52})^{52 \times 5}\\\\A = \$17,253.46

B.) When the interest is charged daily,

As we know that there are 365 days in a year, therefore, n = 365, substitute the values,

A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{365})^{365 \times 5}\\\\A = \$19,554.55

C.) When the interest is charged Continuously,

As we know that the formula for continuous compounding is given as,

A = Pe^{rt}

Substitute the values, we will get,

A = 15000 \times (e^{0.024 \times 5})\\\\A= \$16,912.45

D.) When the interest is charged Monthly,

As we know that there are 12 months in a year, therefore, n = 12, substitute the values,

A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{12})^{12\times 5}\\\\A = \$15211.23

E.) When the interest is charged Semi-annually,

As we know that the interest is charged Semi-annually, therefore, n = 2, substitute the values,

A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{2})^{2\times 5}\\\\A = \$17,237.36

F.) When the interest is charged Quarterly,

As we know that the interest is charged Quarterly, therefore, n = 4, substitute the values,

A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{4})^{4\times 5}\\\\A = \$17,245.7

Learn more about Compound Interest:

brainly.com/question/25857212

4 0
3 years ago
Read 2 more answers
Solve help I’m in the middle of a test
Taya2010 [7]

Answer:

the anser is -16

Step-by-step explanation:

4 0
3 years ago
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