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Mama L [17]
3 years ago
11

Helppppppppppppppp me plzzzzzzz

Mathematics
1 answer:
NeX [460]3 years ago
8 0

Answer:

B = j + H

Step-by-step explanation:

Given:

j = - H + B

Solve the equation for B

j = - H + B

Add H to both sides of the equation

j + H = - H + B + H

j + H = B

B = j + H

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G
qwelly [4]

Answer:

xysu

Step-by-step explanation:

Lois fuzuoxgixufzuda ufzuf

7 0
3 years ago
Simplify this polynomial identity 5(3+6)+2(7+3)
Softa [21]

Answer:

the answer is 65.

Step-by-step explanation:

use order of operations.

5(3+6)+2(7+3)\\15+30+14+6\\45+20\\65

hope this helps :)

3 0
4 years ago
Which ordered pair is a solutionofy=x-4
dusya [7]
X=4
y=-4
hope this helps u out :)
3 0
3 years ago
Describe and correct the error a student made when solving the equation 7=-4(x+7)-3+2x. What is the correct solution?
olga55 [171]

Answer:

7=-4(x+7)-3+2x

BODMAS

7=-4x-28-3+2x

7=-2x-31

7+31=-2x

x=38/2

x= -19

5 0
4 years ago
Solve for m 1/C+1/m=1/z
9966 [12]
Answer:  " m = zC / (C − z) " .
___________________________________
Explanation:
_________________________
Given:  1/C + 1/m = 1/z ;  Solve for "m".

Subtract  "1/C" from each side of the equation:
____________________________________
1/C + 1/m − 1/C = 1/z − 1/C  ;

to get:  1/m = 1/z − 1/C ;
____________________________________
Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
_________________

mzC {1/m = 1/z − 1/C} ;

to get:  zC = mC − mz ;

Factor out an "m" on the "right-hand side" of the equation:

zC = m(C − z) ;  Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;

zC / (C − z) = m(C − z) / m ;  to get:   24/8 = 3  24

zC/ (C − z) = m ;   ↔   m = zC/ (C − z) .
___________________________________________________
4 0
3 years ago
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