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Vika [28.1K]
3 years ago
11

Describe and correct the error a student made when solving the equation 7=-4(x+7)-3+2x. What is the correct solution?

Mathematics
1 answer:
olga55 [171]3 years ago
5 0

Answer:

7=-4(x+7)-3+2x

BODMAS

7=-4x-28-3+2x

7=-2x-31

7+31=-2x

x=38/2

x= -19

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Given the trinomial, what is the value of the coefficient 'B' in the factored form?. . 2x^2 + 14xy - 36y^2 = 2(x + By)(x - 2y).
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The value of the coefficient B is 9.

2(x+By)(x-2y)
=2(x^2 -2xy +Bxy -2By^2)
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The original form is 2x^2 + 14xy - 36y^2

-36y^2 = -4By^2
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xy(-4 +2B)= 14xy
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Answer:

\large\boxed{7.\ B.\ 8s^2+16s+1}\\\\\boxed{8.\ D.\ -15t^9u^{11}}\\\\\boxed{11.\ C.\ 3,\ -2}

Step-by-step explanation:

7.\\(3s^2+7s+2)+(5s^2+9s-1)=3s^2+7s+2+5s^2+9s-1\\\\\text{combine like terms}\\\\=(3s^2+5s^2)+(7s+9s)+(2-1)\\\\=8s^2+16s+1

8.\\(-3t^2u^3)(5t^7u^8)=(-3\cdot5)(t^2t^7)(u^3u^8)\qquad\text{use}\ a^na^m=a^{n+m}\\\\=-15t^{2+7}u^{3+8}=-15t^9u^{11}

11.\\n-the\ number\\\\n^2=n+6\qquad\text{subtract}\ n\ \text{and}\ 6\ \text{from both sides}\\\\n^2-n-6=0\\\\n^2+2n-3n-6=0\\\\n(n+2)-3(n+2)=0\\\\(n+2)(n-3)=0\iff n+2=0\ \vee\ n-3=0\\\\n+2=0\qquad\text{subtract 2 from both sides}\\n=-2\\\\n-3=0\qquad\text{add 3 to both sides}\\n=3

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