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White raven [17]
3 years ago
13

HELP PLS? BRAINLIST WILL BE REWARDED

Mathematics
1 answer:
GarryVolchara [31]3 years ago
8 0

Answer:

Step-by-step explanation:

y = \frac{1}{5}x + 2

Find two points

When x = 0 ,  y = 0 + 2 = 2

D(0 , 2)

When x = 5;

    y=\frac{1}{5}*5+2= 1 + 2 = 3

E(5, 3)

Plot (0, 2 ) and (5 , 3) in the graph and join the points. This will be the line for the equation y =(1/5)x + 2

y = -x + 8

When x =4 ,  y = -4 + 8 = 4

A(4 , 4)

When x = 6 ;   y = -6 + 8 = 2

B(6 , 2)

Plot (4,4) and (6, 2) in the graph and join the points. This will be the line for the equation y = - x + 8.

This lines will intersect at  point (5,3) and  that point will be the solution of the equation.

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A drilling crew dug to a depth of 26 ½ feet during their first day of drilling. On the second day, the crew dug down 9½ feet mor
Neporo4naja [7]

The depth of the bottom of the hole after the second day is 36 feet using addition operation.

<h3>What is addition?</h3>

In math, addition is the process of adding two or more integers together. Addends are the numbers that are added, while the sum refers to the outcome of the operation.

Given the depth on the first day is 26 ½ feet.

Depth on the second day = 9½ feet more than on the first day i.e. 9½ feet + depth on the first day

This implies, depth on the second day = 9½ + 26 ½

= 36 feet

Therefore, the depth of the bottom of the hole after the second day is 36 feet.

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5 0
1 year ago
F(x)=|x+3|-1 range and domain
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Hey there! :)

Answer:

Domain: (-∞, ∞)

Range: [-1, ∞)

Step-by-step explanation:

This is an absolute-value function.  (Graphed below) The vertex is at (-3, -1) which consists of the minimum y-value of the function. Therefore:

Domain: (-∞, ∞)

Range: [-1, ∞)

8 0
3 years ago
What fractional part of one gallon would fit in one quart
babymother [125]
<span>1/4 1 gallon = 4 quarts 1 quart = 0.25 <span>gallon
I hope this helped!
</span></span>
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Newton’s law of cooling states that the temperature of an object changes at a rate proportionalto the difference between the tem
Verizon [17]

Answer:

\frac{dT}{dt} = -0.05\;min^{-1}  (T-70\ºF)

Step-by-step explanation:

Hi!

Lets call:

T = temprature of the object

T₀ = temperature of surroundings

t = time

The rate of change of T is its derivative with respecto to time. If T > T₀, the object looses heat, so T decreases. Then, being k > 0:

\frac{dT}{dt} = -k(T-T_0) \\

In this case T₀ = 70ºF and k = 0.05/min. Then the differential equation is:

\frac{dT}{dt} = -0.05\;min^{-1}  (T-70\ºF)

3 0
3 years ago
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