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White raven [17]
3 years ago
13

HELP PLS? BRAINLIST WILL BE REWARDED

Mathematics
1 answer:
GarryVolchara [31]3 years ago
8 0

Answer:

Step-by-step explanation:

y = \frac{1}{5}x + 2

Find two points

When x = 0 ,  y = 0 + 2 = 2

D(0 , 2)

When x = 5;

    y=\frac{1}{5}*5+2= 1 + 2 = 3

E(5, 3)

Plot (0, 2 ) and (5 , 3) in the graph and join the points. This will be the line for the equation y =(1/5)x + 2

y = -x + 8

When x =4 ,  y = -4 + 8 = 4

A(4 , 4)

When x = 6 ;   y = -6 + 8 = 2

B(6 , 2)

Plot (4,4) and (6, 2) in the graph and join the points. This will be the line for the equation y = - x + 8.

This lines will intersect at  point (5,3) and  that point will be the solution of the equation.

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Please solution and answer a and b thanks you ​
Igoryamba

Answer:

A) 2280 and length is 12mm and width is 190mm

B) 190, 12

Step-by-step explanation:

Area of 1 cylinder: 456

456*5= 2280

38*5=190

diameter:190mm

height:12mm

190*12= 2280

5 0
3 years ago
Is it true or false that a bbinomial can have a degree of zero?
Mumz [18]

No, because any real valued term with degree 0 would be a constant. All constants in an expression can be combined into single term. Therefore if the expression were of degree 0, all the terms would be constants and could be combined into a single term making the expression a monomial.

6 0
3 years ago
Read 2 more answers
Choose true or false for each statement about the equation (x+14)^1/2 = x+2
vladimir2022 [97]

Answer:

The answer is false

Hope this helps !

Mark me brainliest if I'm right :)

5 0
3 years ago
Work out th following in standard form 3000 x 5000
Sedaia [141]
5x10^3 is the answer 
5 0
3 years ago
Read 2 more answers
Let y′′′−9y′′+20y′=0. find all values of r such that y=erx satisfies the differential equation. if there is more than one correc
DerKrebs [107]

we are given

differential equation as

y'''-9y''+20y'=0

we are given

y=e^{rx}

Firstly, we will find y' , y'' and y'''

those are first , second and third derivative

First derivative is

y'=re^{rx}

Second derivative is

y''=r*re^{rx}

y''=r^2e^{rx}

Third derivative is

y'''=r^2*re^{rx}

y'''=r^3e^{rx}

now, we can plug these values into differential equation

and we get

r^3 e^{rx}-9r^2 e^{rx}+20re^{rx}=0

now, we can factor out common terms

e^{rx}(r^3 -9r^2 +20r)=0

we can move that term on right side

(r^3 -9r^2 +20r)=0

now, we can factor out

r(r^2 -9r +20)=0

r(r-5)(r-4)=0

now, we can set them equal

r=0

r-5=0

r=5

r-4=0

r=4

so, we will get

r=0,4,5...............Answer

4 0
3 years ago
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