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3 years ago

Charlie invests £1200 at 3.5% per annum compound interest.

Mathematics

1 answer:

lbvjy [14]3 years ago

6 0

Answer:

Step-by-step explanation:

Using the compound interest formula $A = P(1+\frac{r}{n} )^{nt}$

A = amount compounded after n years

P = principal (amount invested)

r = rate (in %)

t = time (in years)

n = time used to compound the money

Given P = £1200., r = 3.5%, t = 3years, n = 1 year(compounded annually)

$A = 1200(1+0.035)^{3}\\ A = 1200(1.035)^{3}\\ A = 1200* 1.108717875\\A = 1,330.46$

Value of Charlie's investment after 3 years is £1,330.46

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