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3 years ago

Charlie invests £1200 at 3.5% per annum compound interest.

Mathematics

1 answer:

lbvjy [14]3 years ago

6 0

Answer:

Step-by-step explanation:

Using the compound interest formula $A = P(1+\frac{r}{n} )^{nt}$

A = amount compounded after n years

P = principal (amount invested)

r = rate (in %)

t = time (in years)

n = time used to compound the money

Given P = £1200., r = 3.5%, t = 3years, n = 1 year(compounded annually)

$A = 1200(1+0.035)^{3}\\ A = 1200(1.035)^{3}\\ A = 1200* 1.108717875\\A = 1,330.46$

Value of Charlie's investment after 3 years is £1,330.46

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Write a formula for quadratic function if its graph has the vertex at point (0,6) and passes through the point (−1,−2).

d1i1m1o1n [39]

Answer:

y = - 8x² + 6

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (0, 6), thus

y = a(x - 0)² + 6, that is

y = ax² + 6

To find a substitute (- 1, - 2) into the equation

- 2 = a(- 1)² + 6, that is

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3 years ago

The temperature in Hokkaido in Japan was -8 degrees at 24:00 one night. By 09:00 the temperature had risen 12 degrees. What was

likoan [24]

Answer:

Step-by-step explanation:

On a number line you will got to -8 and go up 12 and you would get 4

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3 years ago

Write each expression as a single power of 10

swat32

Answer:

It is

${10}^{5}$

Step-by-step explanation:

$\frac{ {10}^{4}. {10}^{5} . {10}^{6} }{ {10}^{3} . {10}^{7} } = \frac{ {10}^{(4 + 5 + 6)} }{ {10}^{(3 + 7)} } \\ \\ = \frac{ {10}^{15} }{ {10}^{10} } \\ \\ = {10}^{(15 - 10)} \\ = {10}^{5}$

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3 years ago

Sorry to waste time, but could you help? 5/3(4/3a+9b+2/3a) simplified, take your time! I’m not the best at math so :p

mixas84 [53]

Answer:

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Step-by-step explanation:

(

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3 years ago

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balandron [24]

Answer:

The sequence of transformations that maps triangle XYZ onto triangle X"Y"Z" is translation 5 units to the left, followed by translation 1 unit down, and relfection accross the x-axis.

Explanation:

By inspection (watching the figure), you can tell that to transform the triangle XY onto triangle X"Y"Z", you must slide the former 5 units to the left, 1 unit down, and, finally, reflect it across the x-axys.

You can check that analitically

Departing from the triangle: XYZ

Translation 5 units to the left: (x,y) → (x - 5, y)

Vertex X: (-6,2) → (-6 - 5, 2) = (-11,2)

Vertex Y: (-4, 7) → (-4 - 5, 7) = (-9,7)

Vertex Z: (-2, 2) → (-2 -5, 2) = (-7, 2)

Translation 1 unit down: (x,y) → (x, y-1)

(-11,2) → (-11, 2 - 1) = (-11, 1)

(-9,7) → (-9, 7 - 1) = (-9, 6)

(-7, 2) → (-7, 2 - 1) = (-7, 1)

Reflextion accross the x-axis: (x,y) → (x, -y)

(-11, 1) → (-11, -1), which are the coordinates of vertex X"

(-9, 6) → (-9, -6), which are the coordinates of vertex Y""

(-7, 1) → (-7, -1), which are the coordinates of vertex Z"

Thus, in conclusion, it is proved that the sequence of transformations that maps triangle XYZ onto triangle X"Y"Z" is translation 5 units to the left, followed by translation 1 unit down, and relfection accross the x-axis.

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3 years ago