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3 years ago

8

Lynn is tracking the progress of her plant's growth. Currently the plant is 11 The plant grows 1.2 cm per day. Find an equation

that represents the plant's height after any given number How tall is the plant after 9 days?

2 answers:

Drupady [299]3 years ago

8 0

Answer:

the equation is 11+1.2d= h so the height after 9 days would be 21.8cm

Step-by-step explanation:

sasho [114]3 years ago

3 0

Answer:

f(h) = 11 + 1.2h

f(9) = 21.8 cm

Step-by-step explanation:

let 'h' = height

f(h) = 11 + 1.2h

height after 9 days:

f(9) = 11 + 1.2(9)

= 11 + 10.8

= 21.8 cm

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A typical sugar cube has an edge length of 1.00 cm. Imagine you have a cubical box that contains a mole of sugar cubes, perfectl

alisha [4.7K]

Answer:

844368.7 m

Step-by-step explanation:

We are given that a typical sugar cube has an edge length of 1.00 cm.

We have to find the edge length of the box in meters.

Edge length of sugar cube=1 cm = $10^{-2}m$ ( $1 cm=\frac{1}{100}m$ )

Volume of a sugar cube= $side\times side\time side=(10^{-2})^3=10^{-6}m^3$

1 mole of sugar= $6.02\times 10^{23}units$

Volume of 1 unit= $10^{-6} m^3$

Volume of $6.02\times 10^{23}$ units= $6.02\times10^{23}\times 10^{-6}=6.02\times 10^{17} m^3$

Volume of box=1 mole of sugar= $6.02\times 10^{17} m^3$

Edge length of box= $\sqrt[3]{6.02\times 10^{17}}=844368.7 m$

6 0

3 years ago

Points A(2,2) and B(7,14) are two vertices of an equilateral

Dvinal [7]

Answer:

poi nts

Step-by-step explanation:

7

7 0

3 years ago

Answer if you know

Arlecino [84]

I've attached a plot of one such cross-section (orange) over the region in the x-y plane (blue), including the bounding curves (red). (I've set $y=1.25$ for this example.)

The length of each cross section (the side lying in the base) has length determined by the horizontal distance $x$ between the y-axis $x=0$ and the curve $y=\sqrt x$ . In terms of $y$ , this distance is $x=y^2$ . The height of each cross section is twice the value of $y$ , so the area of each rectangular cross section should be $2y^3$ .

This means the volume would be given by the integral

$\displaystyle\int_0^22y^3\,\mathrm dy$

8 0

3 years ago

Ten engineering schools in the United States were surveyed. The sample contained 250 electrical engineers, 80 being women; 175 c

steposvetlana [31]

Answer:

There is a significant difference between the two proportions.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for difference between population proportions is:

$CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}$

Compute the sample proportions as follows:

$\hat p_{1}=\frac{80}{250}=0.32\\\\\hat p_{2}=\frac{40}{175}=0.23$

The critical value of <em>z</em> for 90% confidence interval is:

$z_{0.10/2}=z_{0.05}=1.645$

Compute a 90% confidence interval for the difference between the proportions of women in these two fields of engineering as follows:

$CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}$

$=(0.32-0.23)\pm 1.645\times\sqrt{\frac{0.32(1-0.32)}{250}+\frac{0.23(1-0.23)}{175}}\\\\=0.09\pm 0.0714\\\\=(0.0186, 0.1614)\\\\\approx (0.02, 0.16)$

There will be no difference between the two proportions if the 90% confidence interval consists of 0.

But the 90% confidence interval does not consists of 0.

Thus, there is a significant difference between the two proportions.

4 0

3 years ago

What is -4R-2r+5 as a simpler exspression

enyata [817]

$\sf-4R-2r+5$ is already in simplest form.

But if you meant to say $\sf-4r-2r+5$ , we would combine the first two terms.

Adding/subtracting like terms is the same as adding/subtracting whole numbers.

$\sf-4-2=-6$

Therefore:

$\sf-4r-2r=-6r$

Which gives us:

$\boxed{\sf-6r+5}$

8 0

4 years ago

Read 2 more answers