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igomit [66]
3 years ago
9

355 divided 14 hiksdjkndndf

Mathematics
1 answer:
vaieri [72.5K]3 years ago
4 0

Answer:

Rounded to the nearest whole number is 25

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Help pls i have 5 minss, no links
KonstantinChe [14]

Answer:

3/25

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Melissa used her credit card to buy a $745 refrigerator. She kept the refrigerator for exactly nine years, during which time it
NemiM [27]

Answer:

37.77

Step-by-step explanation:

P= PV x i / 1- (1+i)^-n

PV = 745

I = .1684 / 12 = .01403

N = 4 x 12 = 48

.19 x (365 x 9) = 624.53

21.4338469 x 48= 1028.12

624.53 / (624.53+1028.12) = 37.77

5 0
3 years ago
Please help with at least one of these ( I accept 1 answer if you have it; make sure you are 100% positive its correct though!)
Trava [24]

So I know some of them but not all them sorry

5. If m<5=70 then m<6= <em><u>20</u></em>

<em>Why? </em> Because there is a 90 degree angle there and if m<5 is 70 all you have to do to get m<6 is subtract 70 from 90 and you get 20 degrees

6. If m<5=70 then m<1= <em><u>90 </u></em> and m<4=<em><u>90 </u></em>

<em>Why? </em>Because you can see based on the drawing that they form right angles

4a. FGK is right angles

4b. The measure of FGK is 90 in total

<em>Why? </em> It has the right angle

Hope this helps:) this was all I could remember

8 0
3 years ago
. A binary string containing M 0’s and N 1’s (in arbitrary order, where all orderings are equally likely) is sent over a network
Sophie [7]

Answer:

P(k) = \frac{\binom{N}{k} \binom{(M+N) - N}{r-k}}{\binom{M+N}{r}}

Step-by-step explanation:

We can model the string as a hypergeometric distribution, as each bit has two possible values, 1 or 0, and the chance of a 1 or 0 changes with every bit, as there are a finite number M of 0's and N of 1's and every bit takes one of those values.

If M+N (total size of the string) >> r (number of trials), we could model it as a binomial distribution as the probability of a 1 or 0 wouldn't change in a significant amount with every bit, but as we don't know the magnitude of M+N and r, we follow up with hypergeometric distribution.

The distribution has the following formula for probability:

P(k) = \frac{\binom{K}{k} \binom{N - K}{n-k}}{\binom{N}{n}}

Where k is the number of sucesses, K is how many total sucess states are in the population, N is the population size and n is the number of draws.

For our case, a 1 would be a sucess, i.e. k the number of 1's we want to know the probability, N our total number of 1's, M+N the length of the string (population size) and we want to analyse what happens in the first r bits (number of draws):

P(k) = \frac{\binom{N}{k} \binom{(M+N) - N}{r-k}}{\binom{M+N}{r}}

8 0
3 years ago
A furnace operates at 2,300°F.
Cloud [144]

Answer:

T = 2,300 + q × 250

6 0
3 years ago
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