Reabilwe is conducting an experiment in which the temperature is measured carefully. The temperature was 106°C at the end of the
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Cross sections of the volume are washers or annuli with outer radii <em>x(y)</em> + 1, where
<em>y</em> = <em>x(y) </em>² - 1 ==> <em>x(y)</em> = √(<em>y</em> + 1)
and inner radii 1. The distance between the outermost edge of each shell to the axis of revolution is then 1 + √(<em>y</em> + 1), and the distance between the innermost edge of <em>R</em> on the <em>y</em>-axis to the axis of revolution is 1.
For each value of <em>y</em> in the interval [-1, 3], the corresponding cross section has an area of
<em>π</em> (1 + √(<em>y</em> + 1))² - <em>π</em> (1)² = <em>π</em> (2√(<em>y</em> + 1) + <em>y</em> + 1)
Then the volume of the solid is the integral of this area over [-1, 3]:
The number of bags of chips sold is 8 and the number of packs of cookies sold is 12
<em><u>Solution:</u></em>
Let "a" be the number of bags of chips sold
Let "b" be the number of packs of cookies sold
Given that,
Cost of one bag of chips = $ 1.50
Cost of one pack of cookies = $ 1.25
Yesterday Abigail made $27 from selling a total of 20 bags of chips and packs of cookies
<em><u>So we can frame a equation as:</u></em>
Number of bags of chips sold + number of packs of cookies sold = 20
a + b = 20 ---- eqn 1
Also given that Abigail made $27 from selling
number of bags of chips sold x Cost of one bag of chips + number of packs of cookies sold x Cost of one pack of cookies = $ 27
1.5a + 1.25b = 27 ---- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "b"</u></em>
From eqn 1,
a = 20 - b ---- eqn 3
Substitute eqn 3 in eqn 2
1.5(20 - b) + 1.25b = 27
30 - 1.5b + 1.25b = 27
-0.25b = -3
<h3>b = 12</h3>Therefore from eqn 3,
a = 20 - b = 20 - 12 = 8
<h3>a = 8</h3><em><u>Thus we have:</u></em>
number of bags of chips sold = 8
number of packs of cookies sold = 12
Answer:
t= 0
Step-by-step explanation:
Using the rules of logarithms
log x + log y = log(xy)
1 = 0
Given
a +
= t ,then
(a ×
) = t
1 = t , thus
t = 0