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3 years ago

I need help with the question that is attached.

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

3 0

Answer:

69˚

Step-by-step explanation:

138/2 = 69

m<E = 69˚

<E nad <H are equal, so H is also 69˚

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Another easy math no scam links

algol13

Answer:

Step-by-step explanation:

x = 8

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3 years ago

Read 2 more answers

In a collision, a 5 kg mass moving at 2m/s transfers all of its momentum to a 1 kg mass. What is the velocity of the 1kg mass af

statuscvo [17]

Answer:
velocity = 10 m/sec in the same direction as the first body did

Explanation:
The momentum of the body can be calculated as follows:
momentum = mass * velocity

For the first body, we have:
mass = 5 kg
velocity = 2 m/sec
momentum = mass * velocity
momentum = 5 * 2 = 10 kg.m/sec

We know that this momentum is transferred completely to the second body

For the second bode, we have:
momentum = 10 Kg.m/sec
mass = 1 kg
momentum = mass * velocity
10 = 1 * velocity
velocity = 10/1
velocity = 10 m/sec

Finally, we should get the direction of the motion:
Both the velocity of the first and second bodies have positive values. Therefore, the second body is moving in the same direction as the first body did.

Hope this helps :)

6 0

3 years ago

Read 2 more answers

Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the

ANTONII [103]

Answer:

Length of right-angle triangle 'a' = 4

$sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}$

$cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}$

$tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}$

Step-by-step explanation:

Step(i):-

Given b = 3 and hypotenuse c = 5

Given ΔABC is a right angle triangle

By using pythagoras theorem

c² = a² + b²

⇒ a² = c² - b²

⇒ a² = 5²-3²

=25 - 9

a² = 16

⇒ a = √16 = 4

The sides of right angle triangle a = 4 ,b = 3 and c = 5

Step(ii):-

$sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}$

$cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}$

$tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}$

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3 years ago

Find the domain and range of the relation and determine whether it is a function.

Anna [14]

The correct answer to this question is this "domain: x > 1; range: y > 0; Yes, it is a function."

Based from the graph, it has a vertical asymptote at x = 1, so domain is x > 1 and since it has horizontal asymptote at y=0, its range is y > 0. So this concludes us to have a domain of x > 1 and a range of y > 0.

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3 years ago

When is it logical to use 22/7 instead of 3.14 for pi

Ugo [173]

You should use 22/7 when you are dealing with other fractions.

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3 years ago