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3 years ago

What geometric figure is the union of two non-collinear rays AB and AC? AC?

Mathematics

1 answer:

Jobisdone [24]3 years ago

5 0

Answer:

angle bac is the answer

Step-by-step explanation:

both rays emanate from the shared point 'a', which will be the vertex of angle bac

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Mathematical Statement Justification

olya-2409 [2.1K]

Answer:

Step-by-step explanation:

1. Given mathematical statement

$4x+3=x+5-2x$

So,

$\begin{array}{cc}4x+3=x+5-2x&\text{ Given}\end{array}$

2. Rewrite it as

$4x+3=x-2x+5$

So,

$\begin{array}{cc}4x+3=x-2x+5&\text{ Commutative property of addition}\end{array}$

3. Combine like terms $x$ and $-2x:$

$4x+3=-x+5$

So,

$\begin{array}{cc}4x+3=-x+5&\text{ Combine like terms}\end{array}$

4. Add $x$ to both sides:

$4x+3+x=-x+5+x\\ \\5x+3=5$

So,

$\begin{array}{cc}5x+3=5&\text{ Addition property of equality}\end{array}$

5. Subtract 3 from both sides:

$5x+3-3=5-3\\ \\5x=2$

So,

$\begin{array}{cc}5x=2&\text{ Subtraction property of equality}\end{array}$

6. Divide both sides by 5:

$x=\dfrac{2}{5}$

So,

$\begin{array}{cc}x=\dfrac{2}{5}&\text{ Division property of equality}\end{array}$

6 0

3 years ago

Read 2 more answers

What’s the correct answer for this?

Lynna [10]

Answer:

Step-by-step explanation:

tan x= 6/8

usually tan θ = perpendicular / base

So,

we get perpendicular = 6, base = 8

Now using Pythagorean Theorem to find hypotenuse

hyp² = base² + Perp²

hyp² = 8² + 6²

hyp²= 64 + 36

hyp²=100

Taking sq root on both sides

hypotenuse = 10

Now

sin θ = Perpendicular / Hyp

sin x = 6 / 10

Now

cos θ = base / Hyp

cos x = 8 / 10

6 0

3 years ago

Meredith is playing games at an arcade to earn tickets that she can exchange for a prize. She has 294 tickets from previous visi

grin007 [14]

First, plug in 448 for y:

448=7x+294

Secondly, subtract 294 from both sides to isolate x:

154=7x

Divide both sides by 7:

22=x

Refine:

x=22

The answer is D)22

8 0

3 years ago

Read 2 more answers

What is the FCC of 12 and 30? How to use the gcf to factor 12+30

Leno4ka [110]

Can i get time to answer this question.

3 0

3 years ago

What is the area of a sector with a central angle of (2pi/3) radians and a diameter of 12 in?

Stels [109]

Answer:

The area of the sector is $37.68\ in^{2}$

Step-by-step explanation:

step 1

Find the area of the circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=12/2=6\ in$ ----> the radius is half the diameter

substitute

$A=(3.14)(6)^{2}$

$A=113.04\ in^{2}$

step 2

Find the area of a sector with a central angle of (2pi/3)

Remember that

The area of $113.04\ in^{2}$ subtends a central angle of $2\pi \ radians$

by proportion

Let

x----> the area of the sector

$\frac{2\pi}{113.04}=\frac{(2\pi/3)}{x}\\ \\x=113.04*(2\pi/3)/(2\pi)\\ \\x=37.68\ in^{2}$

8 0

3 years ago