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Evgen [1.6K]
3 years ago
10

Alicia, Malik, Joey, and Hailey had some pencils. Alicia gave 18 pencils to Malik. She received 10 pencils from Joey and 23 penc

ils from Hailey. Alicia had 76 pencils in the end. How many pencils did she have in the beginning? ​
Mathematics
2 answers:
strojnjashka [21]3 years ago
6 0

Answer:

61

Step-by-step explanation:

subtract the ones she got add the ones she gave away

Margaret [11]3 years ago
5 0

Answer:

Alicia had 61 pencils

Step-by-step explanation:

Alicia had 76 pencils at the end, gave 18 pencils, and received a total of 33 pencils. 33-18 = 15. Alicia gains 15 pencils. To figure out how many she already had we subtract 76 to 15. 76-15 = 61. To check this we can make an equation. 61-18+10+23 = 76. 76 = 76 so Alicia had 61 pencils in the begginning.

If this helped I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

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sattari [20]
(k - 34) x 9 =72
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k - 34 = 8
k = 8 + 34
k = 42
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3 years ago
Complete the sentence: similar figures have the
umka21 [38]
I'm assuming it would be the same shape? That's also assuming that it's referring to congruent shapes and angles. 
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3 years ago
Derivative of<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20-%202x%20-%201%20%7D%7B%20%7Bx%7D%5E%7B2
Anastaziya [24]

Answer:

\displaystyle  \frac{dy}{dx} =    \frac{2x + 2}{x^3}

Step-by-step explanation:

we would like to figure out the derivative of the following:

\displaystyle  \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }

to do so, let,

\displaystyle y =  \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }

By simplifying we acquire:

\displaystyle y =  3 -  \frac{2}{x}  -  \frac{1}{ {x}^{2} }

use law of exponent which yields:

\displaystyle y =  3 -  2 {x}^{ - 1}  -   { {x}^{  - 2} }

take derivative in both sides:

\displaystyle  \frac{dy}{dx} =  \frac{d}{dx}  (3 -  2 {x}^{ - 1}  -   { {x}^{  - 2} } )

use sum derivation rule which yields:

\rm\displaystyle  \frac{dy}{dx} =  \frac{d}{dx}  3 -   \frac{d}{dx} 2 {x}^{ - 1}  -     \frac{d}{dx} {x}^{  - 2}

By constant derivation we acquire:

\rm\displaystyle  \frac{dy}{dx} =  0 -   \frac{d}{dx} 2 {x}^{ - 1}  -     \frac{d}{dx} {x}^{  - 2}

use exponent rule of derivation which yields:

\rm\displaystyle  \frac{dy}{dx} =  0 -   ( - 2 {x}^{ - 1 -1} ) -     ( - 2 {x}^{  - 2 - 1} )

simplify exponent:

\rm\displaystyle  \frac{dy}{dx} =  0 -   ( - 2 {x}^{ -2} ) -     ( - 2 {x}^{  - 3} )

two negatives make positive so,

\displaystyle  \frac{dy}{dx} =   2 {x}^{ -2} +      2 {x}^{  - 3}

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

\displaystyle  \frac{dy}{dx} =   \frac{2 }{x^2}+       \frac{2}{x^3}

simplify addition:

\displaystyle  \frac{dy}{dx} =    \frac{2x + 2}{x^3}

and we are done!

5 0
3 years ago
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ivanzaharov [21]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
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