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nika2105 [10]
3 years ago
11

Find the missing value for each rectangular prism. Volume: 8 2/3 Length:? Width: 4 1/3 Height: 2/3

Mathematics
1 answer:
Rainbow [258]3 years ago
7 0

Answer:

3 2/3 = length

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Write an equation for a rational function with: Vertical asymptotes at x = -1 and x = 3 x intercepts at x = -2 and x = -6 Horizo
dlinn [17]

Answer:

\frac{7(x+2)(x+6)}{(x+1)(x-3)}

Step-by-step explanation:

The vertical asymptotes need to be in the denominator. They become VA's when that small expression value equals zero.

x=-2 will become (x+2)

and x=-6 will become (x+6)

The x intercepts will be in the numerator.

x=-1 will go with (x+1) and x=3 will go with (x-3)

The horizontal A must be the quotient of the coefficient of the numerator and denominator, since both the top and bottom have the same power.

To make the quotient 7, we place a seven in the numerator so 7/1=7.

6 0
3 years ago
( 9 × 10*3)( 2 × 10*10)
Snezhnost [94]
9000+20000000000=?!!!!!
3 0
4 years ago
In an arboretum, the heights of five trees were 21 feet, 31 feet, 36 feet, 28 feet,
lbvjy [14]

Answer:

26

Step-by-step explanation:

(21+31+36+28+26+x)/6=28

21+31+36+28+26+x= 28×6

142+x =168

x=168-142

x=26

6 0
3 years ago
Rectangle ABCD is shown with diagonal AC drawn. Point F is on AC and point E on DC such that FE is perpendicular to DC. Prove tr
777dan777 [17]

Triangle ABC is similar to triangle CEF.

<u>Explanation:</u>

<u></u>

Diagram is inserted for the reference.

ABCD is a rectangle.

ABC is a right angled triangle because all the angles of the rectangle are 90◦ - (a)

CEF is a right angled triangle because FE is perpendicular to DC – (b)

In triangles ABC and CEF,

1. Angle ABC = Angle CEF = 90◦ (Both are right angles from a and b)

2. Angle BCA = Angle EFC (Alternate angles on parallel lines are equal on intersection)

Hence using Similarity property of AA (Angle, Angle), Triangle ABC and CEF are similar.

<u></u>

5 0
3 years ago
choose the equation that represents a line that represents a line that passes through points -3, 2 and 2,1 A. 5x+y=-13 B. 5x-y=1
Mrrafil [7]

bearing in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-2}{2-(-3)}\implies \cfrac{-1}{2+3}\implies -\cfrac{1}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-\cfrac{1}{5}[x-(-3)]\implies y-2=-\cfrac{1}{5}(x+3)

\bf y-2=-\cfrac{1}{5}x-\cfrac{3}{5}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{5}}{5\left(y-2 \right)=5\left( -\cfrac{1}{5}x-\cfrac{3}{5} \right)}\implies 5y-10=-x-3 \\\\\\ 5y=-x+7\implies x+5y=7

6 0
4 years ago
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