Answer:
Step-by-step explanation:
“the center of the ellipse is located below the given co-vertex”
Co-vertex and center are vertically aligned, so the ellipse is horizontal.
Equation for horizontal ellipse:
(x-h)²/a² + (y-k)²/b² = 1
with
a² ≥ b²
center (h,k)
vertices (h±a, k)
co-vertices (h, k±b)
foci (h±c,k), c² = a² -b²
One co-vertex is (-8,9), so h = -8.
One focus is (4,4), so k = 4.
Center (h,k) = (-8,4)
c = distance between center and focus = |-8 - 4| = 12
b = |9-k| = 5
a² = c² + b² = 169
(x+8)²/169 + (y-4)²/25 = 1
Answer:
2/8 is the answer
Step-by-step explanation:
I think the answer
No, the rectangle cannot have x = 60 and y = 18 because x + y is less than 60
No, the rectangle cannot have x = 60 and y = 18 because x + y is less than 24
Yes, the rectangle can have x = 60 and y = 18 because x = 12 + 2y
Yes, the rectangle can have x = 60 and y = 18 because x = 24 + 2y
