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3 years ago

1. Consider the system of equations below. What could be the first step in solving by elimination?

Mathematics

1 answer:

leva [86]3 years ago

7 0

Answer:

Multiple the first equation by -1

Step-by-step explanation:

After doing this you add the two equations together and follow the systems of equations as normal

$-3x+-5y=-16\\3x+2y=10\\-3y=-6\\\frac{-3y}{-3} =\frac{-6}{-3} \\y=2$

Therefore y = 2

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The area of a trapezoid is 168cm2. The height is 16cm and the length of one of the parallel sides is 9cm. Find the length of the

dmitriy555 [2]

Answer:

12 cm

Step-by-step explanation:

The formula for the area of a trapezoid is written as:

1/2(b1 + b2)h

h = height = 16 cm

b1 = Length of one parallel side = 9cm

b2 = Length of second parallel side = ?

Area of trapezoid = 168cm²

The formula to find the length of the second parallel side =

b2 = 2A/h - b1

b2 = 2 × 168/16 - 9

b2 = 336/16 - 9

b2 = 21 - 9

b2 = 12cm

Therefore, the length of the second parallel side is 12 cm

3 0

3 years ago

Please help me. Brainliest to best answer!

Bingel [31]

Answer:

4y + 48 - 16x = 0 ~Solve for y~

4y = -48 + 16x

y = -12 + 4x

The slope is 4.

We'll use the point (1, 4) and m = 4.

Plug these into the equation: y - y1 = m(x - x1)

y - 4 = 4(x - 1)

y - 4 = 4x - 4

y = 4x

6 0

3 years ago

Please answer this correctly

jolli1 [7]

Answer:

6 times

Step-by-step explanation:

1/9 chance you get the orange marble. If you pick 54 times, you can expect to get the orange marble 6 times.

5 0

3 years ago

Estimate the product of 67 an 73 round each number to the neares tenes

vampirchik [111]

Answer:

4900

Step-by-step explanation:

73*67

70*70

7*7(10^2)

49(100)

4900

6 0

3 years ago

Read 2 more answers

If a die is rolled one time, find probability of getting a number greater than 3 and an odd number.

Nadya [2.5K]

Answer:

$\dfrac{1}{6}$ .

Step-by-step explanation:

It is given that a die is rolled one time. So,

Sample space : $S=\{1,2,3,4,5,6\}$

Number is greater than 3 : $A=\{4,5,6\}$

Number is odd : $A=\{1,3,5\}$

Number greater than 3 and an odd number : $A\cap B=\{5\}$

It is conclude that,

$n(S)=6, n(A)=3,n(B)=3,n(A\cap B)=1$

The probability of getting a number greater than 3 and an odd number is

$P=\dfrac{n(A\cap B)}{n(S)}$

$P=\dfrac{1}{6}$

Therefore, the required probability is $\dfrac{1}{6}$ .

4 0

3 years ago