Since the data is insufficient. Let us denote that n1 = 100, n2 = 100X1 = 38. X2 = 40
So looking for the p value:
p = (38+ 40) / (100 + 100) = 0.39
z = (38/100 - 40/100)/√ (0.39*(1-0.39)*(1/100 + 1/100))= -0.2899
P-value = P (|z| > 0.2899) = 0.7718
Answer:
The answer is 166.666667
Step-by-step explanation:
Okay so we need to find the number that we devide 20 to get 0.12 or 12% what I did was I put x as a varabile so
20/x=0.12
20=0.12x
20/0.12=x
x=166.666667
You havent added the options
Answer:
idk mush
Step-by-step explanation:
i dont have a clue
