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Paul [167]
2 years ago
14

30 points and BRAINLiEST PLS HELP!!

Mathematics
2 answers:
vovikov84 [41]2 years ago
7 0

Answer:

Fr

Step-by-step explanation:

jenyasd209 [6]2 years ago
3 0

Answer:

-0.75

Step-by-step explanation:

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What is the inverse of the function g(x)=5(x-2)
sergeinik [125]

Answer:

\frac{x-2}{5}

Step-by-step explanation:

8 0
3 years ago
3.2% of a population are infected with a certain disease. There is a test for the disease, however the test is not completely ac
Ivenika [448]
Really don’t kno it’s a hard question
6 0
3 years ago
Kwame bought a car for $25,000. The value of the car is decreasing at a rate of 6.5% each year. Write a function that represents
sweet-ann [11.9K]
<h3><u>The function that represents the price P of the car after x years is:</u></h3>

P = 25000(0.935)^x

<em><u>Solution:</u></em>

<em><u>The decreasing function is given as:</u></em>

y = a(1 - r)^t

Where,

y is future value

a is initial value

r is decreasing rate in decimal

t is time period

From given,

a = 25000

r = 6.5 \% = \frac{6.5}{100} = 0.065

number of years = x

future value = P

Therefore,

P = 25000(1 - 0.065)^x\\\\P = 25000(0.935)^x

Thus the function is found

8 0
3 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
Please help! thanks :)
jeka94

Answer:

B- 583

Step-by-step explanation:

6% of 550 is 33. So, you just add 33 to 550 which equals 583.

Your welcome!

3 0
3 years ago
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