40+90=130
180-130=50
50+130=180
x=130
50+x=180
Answer:
5 years
Step-by-step explanation:
We are given;
- Initial value of the car = $12,500
- Rate of Depreciation = 13% per year
- New value (after depreciation) = $6,250 (half the initial value)
We are required to determine the time taken for the value of the car to depreciate to half the original value.
- We need to know the depreciation formula;
- New value = Initial value ( 1 - r/100)^n
Therefore;
$6,250 = $12,500(1 - r/100)^n
0.5 = (1 - 13/100)^n
0.5 = 0.87^n
Introducing log on both sides;
log 0.5 = n log 0.87
Therefore;
n = log 0.5 ÷ log 0.87
= 4.977
= 5 years
Therefore, it takes 5 years for the value of the car to depreciate to half the initial value.
Step-by-step explanation:
Cot of 3pi 4
The exact value of cot(π4) cot ( π 4 ) is 1 . Multiply −1 by 1 .
Window come at me fam I’m smarter than you bruv
Answer:
y = ⁴/3x - 7
Step-by-step explanation:
✔️First, find the slope (m):
Slope (m) = ∆y/∆x = 4/3
m = ⁴/3
✔️Determine the y-intercept (b):
The y-axis is intercepted by the line at y = -7, therefore the y-intercept (b) would be -7.
b = -7
✔️Write the equation:
Substitute the value of m = ⁴/3 and b = -7 into y = mx + b (slope-intercept form equation).
y = ⁴/3x + (-7)
y = ⁴/3x - 7
