Answer (<u>assuming it can be written in slope-intercept form)</u>:
Step-by-step explanation:
1) First, find the slope of the line. Use the slope formula, 
. Substitute the x and y values of the given points into the formula and solve:
So, the slope is 
.
2) Now, use the point-slope formula 
to write the equation of the line. Substitute 
, 
, and 
for real values.
Since represents the slope, substitute for it. Since and represent the x and y values of one point the line intersects, choose from any one of the given points (it doesn't matter which one, either way the result equals the same thing) and substitute its x and y values into the formula as well. (I chose (4,5), as seen below.) From there, isolate y to place the equation in slope-intercept form (
format) and find the following answer:
Why u trying to cheat bruh
Answer:
(3, -3 8/9)
Step-by-step explanation:
Use a slope calculation or a graph to find the slope of the line.
m = (y-y)/(x-x)
m = (-3- -5)/(7- -2)
m = 2/9
Then write the equation of the line. I used point-slope form. (You could use y=mx+b, slope-intercept form, but you'd have to first calculate b as well)
Point-slope form:
y -Y = m(x-X)
y - -3 = 2/9(x- 7)
y + 3 = 2/9(x - 7)
We know the x-coordinate of the point we're looking for is 3. Fill that in as well and calculate the y that goes with it.
y + 3 = 2/9(3-7)
y+3=2/9(-4)
y = -8/9 - 3
y = -3 8/9
In decimal form this is -3.8888repeating
see image.
The point at x=3 on the line between M(7,-3) and N(-2,-5) is (3, -3 8/9).
A = a^2.....where " a " is the size of 1 side
A = 256
256 = a^2...take sqrt of both sides, eliminating the ^2
sqrt 256 = a
16 = a
so each side is 16 ft....now we find the perimeter
P = 4a....where " a " is the size of each side
P = 4(16)
P = 64.......so they will need 64 ft of fencing <===
