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3 years ago

Each day a machine makes 500000 staples and puts them into boxes.

Mathematics

2 answers:

MrRissso [65]3 years ago

6 0

Answer:

3031 boxes

Step-by-step explanation:

Nikitich [7]3 years ago

4 0

Answer:3031 boxes will be filled with staples

Step-by-step explanation:

Given that the machine makes 500000 in a day

So total staples = 500000

Staples in a box = 165

In order to find how many boxes the machine will make, the total number of staples has to be divided by the number of staples in a box.

So,

$number\ of\ boxes = \frac{Total\ staples}{Staples\ in\ a\ box}\\= \frac{500000}{165}\\= 3030.30$

As no staples can be left out of box, we will round off the number to next number.

So,

3031 boxes will be filled with staples

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Which graph represents the function f (x) = StartFraction 4 Over x EndFraction?

beks73 [17]

Answer:

2nd graph (image)

Step-by-step explanation:

The function to graph is:

$f(x)=\frac{4}{x}$

It follows the general pattern of the function: $f(x)=\frac{1}{x}$ , which is general shape and in 1st and 3rd quadrants. So, we can eliminate 3rd and 4th choices (because of quadrants).

The answer is either 1st, or 2nd graph.

Now, we simply can check a point in both.

lets take x = 4, so the function would be:

f(4) = 4/4 = 1

Hence, point is:

(4,1)

The first graph doesn't go through this point. The second graph does.

hence, we can successfully choose the 2nd graph as our answer.

7 0

3 years ago

Read 2 more answers

Use the Quadratic formula to find all real zeros of the 2nd degree polynomial

schepotkina [342]

Answer:

x ∈ {-5, -1}

Step-by-step explanation:

Here's the solution using the quadratic formula:

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-24\pm\sqrt{24^2-4\cdot 4\cdot 20}}{2\cdot 4}\\\\=\dfrac{-24\pm\sqrt{576-320}}{8}=\dfrac{-24\pm\sqrt{256}}{8}\\\\=\dfrac{-24\pm 16}{8}=-3\pm 2=\{-5,-1\}$

The real zeros are -5 and -1.

_____

There are many ways to check your answer. One of them is to look at the given quadratic, which has no changes of sign in its coefficients. (They are all positive.) That means there can be no positive real roots, so already you know that x=0.5 won't work.

Also, the constant in the quadratic is the product of the roots, For your roots, their product is -7/4, so even multiplying by 4 (the leading coefficient in the given quadratic), you don't get anything like 20.

4 0

3 years ago

Hard math question!

luda_lava [24]

First, let me show you some notation.

To show a matrix is an inverse of another matrix, we write $A^{-1}$

-1 is not an exponent. It just shows that a matrix is an inverse of another matrix.

For a 2x2 matrix, we can get the inverse by first making b and c negatives and swap the positions of a and d.

Then multiply each entry in the matrix by 1 divided by the determinant.

$\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]^{-1} = 
 \frac{1}{ad - bc}\left[\begin{array}{ccc}d&{-b}\\{-c}&a\end{array}\right] = \\ \\ \\ \left[\begin{array}{ccc}d(\frac{1}{ad-bc})&{-b}(\frac{1}{ad-bc}) \\ {-c}(\frac{1}{ad-bc}) &a(\frac{1}{ad-bc}) \end{array}\right]$

I hope this helped!

8 0

3 years ago

5 and a half minus 7 equals

gogolik [260]

Answer:

-9/5; -1 4/5; -1.8

Step-by-step explanation:

5 0

3 years ago

The area of rectangular field is 1440 sq meters and perimeter is 152 metre. Out of length or breadth which one is to be decrease

Arturiano [62]

Answer:

If Length is decreased by 10% then it would become a square.

Step-by-step explanation:

Given:

Area of Rectangular field = 1440 sq. m

Perimeter = 152 m.

We need to find which one needs to be decreased by what percentage to make it a square.

Solution:

Let length be denoted by 'l'.

Also Let width be denoted by 'w'.

Now we know that Area of rectangular field is given by Length times width.

framing in equation form we get;

$l\times w = 1440 \ \ \ \ equation\ 1$

Also we know that Perimeter of rectangular field is given by 2 times sum of Length and width.

framing in equation form we get;

$2(l+w) =152\\\\l+w =\frac{152}{2}\\\\l+w=76\\\\l=76-w \ \ \ \ equation \ 2$

Now Substituting equation 2 in equation 1 we get;

$l\times w =1440\\\\(76-w)w=1440\\\\76w-w^2=1440\\\\w^2-76w+1440 =0$

Now we will find the root by factorizing the same we get;

$w^2-36w-40w+1440=0\\\\w(w-36)-40(w-36)=0\\\\(w-36)(w-40) =0 \\$

Now solving for each to find the value of 'w' we get;

$w-36 =0\\\\w=36\\\\also \\\\w-40=0\\\\w=40$

So We can say that;

Width = 36 m and Length = 40 m

Now we need to find out of length or breadth which one is to be decreased by what percentage to make it a square.

We know that square has all sides same.

So from the data we found we can say that if length is decreased by 4 then length and breadth(width) both will be equal.

So to find percentage decreased we will divide length to be decreased by total length and then multiply by 100.

framing in equation form we get;

percentage decreased = $\frac{4}{40}\times 100 = 10\%$

Hence If Length is decreased by 10% then it would become a square.

6 0

3 years ago