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ratelena [41]
3 years ago
8

How is y=-2x a linear equation?

Mathematics
1 answer:
e-lub [12.9K]3 years ago
3 0
Because it lowers by the same amount each time.
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You wish to package a spherical globe inside a cubical box . The diameter of the globe is 30 centimeters . How much empty space
Aneli [31]

Answer:

<h2>The empty inside the box is 12,870 cubic centimeters, approximately.</h2>

Step-by-step explanation:

Givens

  • The diameter of the globe (sphere) is 30 centimeters,
  • The box must has dimensions 30x30.

We need to find each volume to subtract them.

V_{box}=(30cm)^{3}=  27,000 \ cm^{3}

V_{sphere}=\frac{4}{3} \pi (15cm)^{3} \approx 14,130 \cm^{3}

The difference betweem the box and the sphere is

\Delta V=27,000 - 14,130 = 12,870 \ cm^{3}

Therefore, the empty inside the box is 12,870 cubic centimeters, approximately.

5 0
2 years ago
Domino's Pizza cuts their Large pizza into 8 equal slices. What is the area of one of the slices if diameter is 16 inches?
Ksju [112]

Answer:

25.1325

Step-by-step explanation:

16/2= radius of 8. pi*r^2 for 8 is 201.06. 201.06/8(slices) = 25.1325

6 0
2 years ago
Read 2 more answers
The region bounded by y=(3x)^(1/2), y=3x-6, y=0
Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is y = (3x)^{\frac{1}{2} }

⇒ y^{2} = 3x ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

y^{2} - y - 6 = 0

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = \int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx

= \sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}

= [\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} }  }{3}] - [13.5 - 18 - 6 + 12]

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0
3 years ago
A Pell Grant is a type of financial aid that does not need to be paid back. true or false
Inga [223]
I think the answer is true.
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I need help on question number 26
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