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dimaraw [331]
3 years ago
11

Which expression is equivalent to StartFraction b Superscript negative 2 Baseline Over a b Superscript negative 3 Baseline EndFr

action? Assume a not-equals 0, b not-equals 0.
StartFraction a Over b Superscript 5 Baseline
StartFraction 1 Over a b Superscript 5 Baseline Endfraction
StartFraction a cubed b Over 1 EndFraction
StartFraction b Over a EndFraction

Mathematics
2 answers:
Pie3 years ago
8 0

Answer:

D. = \frac{b}{a}

Step-by-step explanation:

Given:

\frac{b^{-2}}{ab^{-3}}

Required:

Assuming a ≠ 0, b ≠ 0, find the expression equivalent to the given expression.

SOLUTION:

\frac{b^{-2}}{ab^{-3}}

Recall the exponent rule =>  \frac{x^{a}}{x^{b}} = x^{a - b}

Applying the exponent rule, we would have:

\frac{b^{-2 -(-3)}}{a}

= \frac{b^{-2 + 3}}{a}

= \frac{b^{1}}{a}

= \frac{b}{a}

Thus, the equivalent expression of \frac{b^{-2}}{ab^{-3}} = \frac{b}{a}

ehidna [41]3 years ago
6 0

Answer:

d

Step-by-step explanation:

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Step-by-step explanation:  

Find the Greatest Common Factor (GCF).

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2. Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

5(15x^2/5+235/5)

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Step-by-step explanation:

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2 years ago
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BigorU [14]

Answer:

The point (8, 4) on the graph represent that:

'Every 8 Minutes, 4 Pictures are Taken.'

Step-by-step explanation:

Since the graph has not been provided lets try to explain in actual context.

The question states that the Graph shows the <u>Number of Pictures</u> a traffic camera takes <u>Each Minute.</u>

This tells us that we have a two-dimensional graph, of x with y where:

x: denotes <em>Each Minute</em>

y: denotes <em>Number of Pictures taken</em>

<em />

<em>Thus x is our </em><u><em>independent </em></u><em>variable that changes, and as a result of it so does y, our </em><u><em>dependent </em></u><em>variable. </em>

As such we can conclude that any point from the graph is of the form

(x,y).

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x=8 and y=4

which if read on the graph it would indicate that:

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3 years ago
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gulaghasi [49]
For the first question
1/x-3, x cannot equal +3. As that would make the denominator 0.
For the second question.
Substitute f(x) into g(x) to get:
x^2 - 3
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