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dimaraw [331]
3 years ago
11

Which expression is equivalent to StartFraction b Superscript negative 2 Baseline Over a b Superscript negative 3 Baseline EndFr

action? Assume a not-equals 0, b not-equals 0.
StartFraction a Over b Superscript 5 Baseline
StartFraction 1 Over a b Superscript 5 Baseline Endfraction
StartFraction a cubed b Over 1 EndFraction
StartFraction b Over a EndFraction

Mathematics
2 answers:
Pie3 years ago
8 0

Answer:

D. = \frac{b}{a}

Step-by-step explanation:

Given:

\frac{b^{-2}}{ab^{-3}}

Required:

Assuming a ≠ 0, b ≠ 0, find the expression equivalent to the given expression.

SOLUTION:

\frac{b^{-2}}{ab^{-3}}

Recall the exponent rule =>  \frac{x^{a}}{x^{b}} = x^{a - b}

Applying the exponent rule, we would have:

\frac{b^{-2 -(-3)}}{a}

= \frac{b^{-2 + 3}}{a}

= \frac{b^{1}}{a}

= \frac{b}{a}

Thus, the equivalent expression of \frac{b^{-2}}{ab^{-3}} = \frac{b}{a}

ehidna [41]3 years ago
6 0

Answer:

d

Step-by-step explanation:

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Answer:

R = \left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right]

Step-by-step explanation:

P - Q + R = I ( I is the identity matrix )

\left[\begin{array}{ccc}2&4\\3&5\\\end{array}\right] - \left[\begin{array}{ccc}-2&2\\4&1\\\end{array}\right] + R = \left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right] ( subtract corresponding elements )

\left[\begin{array}{ccc}2-(-2)&4-2\\3-4&5-1\\\end{array}\right] + R = \left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]

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Step-by-step explanation:

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For one child, a childcare facility charges $350 per month for preschool and $5.00 per hour for each additional hour for after-s
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Answer:

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Step-by-step explanation:

We have the following function  :

f(h)=350+5h (I)

Where f(h) is the monthly fee for after - school care and preschool.

Where h represents the number of hours spent in after - school care.

We know that the total monthly bill for one child was $750 ⇒

f(h)=750

Using (I) we will find the value of the hours ''h'' that verifies the expression ⇒

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Answer:

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