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3 years ago

If Amy Earns 10 Dollars An Hour And She Earned 97.50, How Many Hours Did She Work?

Mathematics

1 answer:

Alborosie3 years ago

3 0

Answer:

9.75 hours or

9 hours and 45 minutes

Step-by-step explanation:

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Using Substitution 4x-3y=-10 and x=1/4y-1

Alinara [238K]

Answer:

Then the solution is (-1/4, 3)

Step-by-step explanation:

Start by eliminating the fractional coefficient 1/4: multiply all 3 terms in the second equation by 4. This results in equation (b), below:

4x - 3y = -10 (a)

4x = y -4 (b)

Substitute y - 4 for 4x in equation (a):

y - 4 - 3y = -10

Combining like terms, we get -2y = -10 + 4, or -2y = -6, or y = 3.

Since x = (1/4)y - 1, if y = 3, then x = (1/4)(3) - 1, or x = 3/4 - 1, or x = -1/4

Then the solution is (-1/4, 3)

7 0

3 years ago

How many hours is 9:13pm from 10:00?

vivado [14]

From 10:00 am I would be 11 hours

5 0

3 years ago

Log4(x^2 + 6x +8) - log4 ( x+2)

vaieri [72.5K]

Since the logarithms have the same base, we can simply divide (x^2 + 6x + 8) by (x+ 2) and just retain the sme base. So, the answer will be Log4(x+4)

6 0

3 years ago

The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.4. This distribution

ankoles [38]

Answer:

a) Normal Distribution

b) 0.146

c) 0.070

Step-by-step explanation:

We are given the following information in the question:

The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.4

a) $\bar{x}$ : mean number of accidents per week at the intersection during a year (52 weeks)

According to central limit theorem, as the sample size becomes larger, the distribution of mean approaches a normal distribution.

Since we have a large sample, the approximate distribution of $\bar{x}$ is a normal distribution with

$\text{Mean} = 2.2\\\text{Standard Deviation} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{1.4}{\sqrt{52}} = 0.19$

b) P(mean is less than 2)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(x > 610)

$P( \bar{x} < 2) = P( z < \displaystyle\frac{2 - 2.2}{0.19}) = P(z < -1.052)$

Calculation the value from standard normal z table, we have,

$P(\bar{x} < 2) = 0.146$

c) P(fewer than 100 accidents at the intersection in a year)

P(x < 100)

$P( \bar{x} < \frac{100}{52}) =P(\bar{x} < 1.92) =P(z < \displaystyle\frac{1.92 - 2.2}{0.19}) = P(z < -1.473)$

Calculation the value from standard normal z table, we have,

$P(x$

7 0

3 years ago

Solve for m. -7 + 4m + 10 = 15 -2m

kykrilka [37]

Answer:

M=2

Step-by-step explanation:

m=2 Make sure to move the terms, then collect the like terms, then subtract, then divide both sides by 6

5 0

3 years ago

Read 2 more answers