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Nikolay [14]
3 years ago
7

Solve for m.-7 + 4m + 10 = 15 -2m​

Mathematics
2 answers:
kolezko [41]3 years ago
7 0

Answer:

m = 2.

Step-by-step explanation:

-7 + 4m + 10 = 15 - 2m

4m + 2m = 15 + 7 - 10

6m = 12

m = 2.

kykrilka [37]3 years ago
5 0

Answer:

M=2

Step-by-step explanation:

m=2 Make sure to move the terms, then collect the like terms, then subtract, then divide both sides by 6

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Anuta_ua [19.1K]

Answer:

17

Step-by-step explanation:

since you are subtracting a negative number it reverses, so you actually ADD the two together

so, 12 1/2 + 4 1/2

add the whole numbers first;

12+4=16

then fractions:

1/2 + 1/2= 1

then all together;

16+1=17!

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3 years ago
y′′ −y = 0, x0 = 0 Seek power series solutions of the given differential equation about the given point x 0; find the recurrence
sukhopar [10]

Let

\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = a_0 + a_1x + a_2x^2 + \cdots

Differentiating twice gives

\displaystyle y'(x) = \sum_{n=1}^\infty na_nx^{n-1} = \sum_{n=0}^\infty (n+1) a_{n+1} x^n = a_1 + 2a_2x + 3a_3x^2 + \cdots

\displaystyle y''(x) = \sum_{n=2}^\infty n (n-1) a_nx^{n-2} = \sum_{n=0}^\infty (n+2) (n+1) a_{n+2} x^n

When x = 0, we observe that y(0) = a₀ and y'(0) = a₁ can act as initial conditions.

Substitute these into the given differential equation:

\displaystyle \sum_{n=0}^\infty (n+2)(n+1) a_{n+2} x^n - \sum_{n=0}^\infty a_nx^n = 0

\displaystyle \sum_{n=0}^\infty \bigg((n+2)(n+1) a_{n+2} - a_n\bigg) x^n = 0

Then the coefficients in the power series solution are governed by the recurrence relation,

\begin{cases}a_0 = y(0) \\ a_1 = y'(0) \\\\ a_{n+2} = \dfrac{a_n}{(n+2)(n+1)} & \text{for }n\ge0\end{cases}

Since the n-th coefficient depends on the (n - 2)-th coefficient, we split n into two cases.

• If n is even, then n = 2k for some integer k ≥ 0. Then

k=0 \implies n=0 \implies a_0 = a_0

k=1 \implies n=2 \implies a_2 = \dfrac{a_0}{2\cdot1}

k=2 \implies n=4 \implies a_4 = \dfrac{a_2}{4\cdot3} = \dfrac{a_0}{4\cdot3\cdot2\cdot1}

k=3 \implies n=6 \implies a_6 = \dfrac{a_4}{6\cdot5} = \dfrac{a_0}{6\cdot5\cdot4\cdot3\cdot2\cdot1}

It should be easy enough to see that

a_{n=2k} = \dfrac{a_0}{(2k)!}

• If n is odd, then n = 2k + 1 for some k ≥ 0. Then

k = 0 \implies n=1 \implies a_1 = a_1

k = 1 \implies n=3 \implies a_3 = \dfrac{a_1}{3\cdot2}

k = 2 \implies n=5 \implies a_5 = \dfrac{a_3}{5\cdot4} = \dfrac{a_1}{5\cdot4\cdot3\cdot2}

k=3 \implies n=7 \implies a_7=\dfrac{a_5}{7\cdot6} = \dfrac{a_1}{7\cdot6\cdot5\cdot4\cdot3\cdot2}

so that

a_{n=2k+1} = \dfrac{a_1}{(2k+1)!}

So, the overall series solution is

\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = \sum_{k=0}^\infty \left(a_{2k}x^{2k} + a_{2k+1}x^{2k+1}\right)

\boxed{\displaystyle y(x) = a_0 \sum_{k=0}^\infty \frac{x^{2k}}{(2k)!} + a_1 \sum_{k=0}^\infty \frac{x^{2k+1}}{(2k+1)!}}

4 0
2 years ago
Please plot this linear equation on a graph, and also explain how to plot it. <br> <img src="https://tex.z-dn.net/?f=y%3D3x-7" i
olasank [31]

Answer:

See below:

Step-by-step explanation:

Hello! I hope you are having a nice day.

We can solve this equation in a single step, we just need a bit of theory and a graph.

We can first see that its in y=mx+b form. Which is also known as Slope-Intercept form.

This means that we know the following.

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Since we know that, we can see that from our equation that the slope of the line is 3 and the y intercept is (0,-7).

Now that we've gotten that, we can start graphing.

The y intercept is -7 so we can plot (0,-7) as one of our points.

The slope of 3 means that we got up 3 units then right a single unit.

Therefore, another point could be (1,-4).

With our two points, we can create our graph by creating a straight line through those two points and therefore plotting our line.

Cheers!

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Mashcka [7]

Answer: 5:4

Step-by-step explanation: you divide them i believe :)

7 0
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