Question

When a baseball is hit by a batter the height of the ball age of T at time TT equals zero is determined by the equation age of T equals -16 T squared +64 2+ 4FT is in seconds for which interval of time is the height of the bar greater than or equal to 52 feet

Answer 1

Answer:

1 ≥ t ≤ 3

Step-by-step explanation:

Given

h(t) = -16t² + 64t + 4

Required

Determine the interval which the bar is at a height greater than or equal to 52ft

This implies that

h(t) ≥ 52

Substitute -16t² + 64t + 4 for h(t)

-16t² + 64t + 4 ≥ 52

Collect like terms

-16t² + 64t + 4 - 52 ≥ 0

-16t² + 64t - 48 ≥ 0

Divide through by 16

-t² + 4t - 3 ≥ 0

Multiply through by -1

t² - 4t + 3 ≤ 0

t² - 3t - t + 3 ≤ 0

t(t - 3) -1(t - 3) ≤ 0

(t - 1)(t - 3) ≤ 0

t - 1 ≤ 0 or t - 3 ≤ 0

t ≤ 1 or t ≤ 3

Rewrite as:

1 ≥ t or t ≤ 3

Combine inequality

1 ≥ t ≤ 3