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3 years ago

Please I need some answers just a few are fine

Mathematics

1 answer:

professor190 [17]3 years ago

3 0

Answer:

a) 16

b) 36

c) 4

d) 81

Explanation:

Finding the square root of a number is the inverse operation of squaring that number. Remember, the square of a number is that number times itself. The perfect squares are the squares of the whole numbers. The square root of a number, n, written below is the number that gives n when multiplied by itself.

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Hi, Help plssss

olga_2 [115]

Answer:

a and b are parallel

Step-by-step explanation:

corresponding angles converse

3 0

2 years ago

Read 2 more answers

I could use some help , i really cant do geometry :(

Gelneren [198K]

Answer:

I am not sure but for

CAE it is 65˚

CBD it is 65˚

Step-by-step explanation:

x+40=3x-10

Move the 3x to the other side by subtracting by 3x on both sides

x-3x+40=3x-3x-10

The equation now looks like this:

-2x+40=-10

Move 40 to the other side by subtracting 40 both sides:

-2x+40-40=-10-40

-2x=-50

Divide by -2 on both sides:

-2x/-2=-50/-2

x=25

Since we found out what x is we can replace x in both CAE and CBD:

For CBD: 25+40 is 65

For CAE: 3(25)-10 is 65

5 0

2 years ago

Read 2 more answers

Evaluate the function at the given numbers( correct to six decimal places). Use the results to guess the value of the limit or e

netineya [11]

Answer:

Value of the limit is 0.5.

Step-by-step explanation:

Given,

$F(x)=\frac{e^x-1-x}{x^2}$

When,

$x=1,F(1)=frac{e^1-1-1}{1}=e-2=0.718281$

$x=0.5, F(0.5)=\frac{e^0.5-1-0.5}{(0.5)^2}=0.594885$

$x=0.1, F(0.1)=\frac{e^0.1-1-0.1}{(0.1)^2}=0.517091$

$x=0.05, F(0.05)=\frac{e^0.05-1-0.05}{(0.05)^2}=0.508438$

$x=0.01, F(0.01)=\frac{e^0.01-1-0.01}{(0.01)^2}=0.501670 \hfill (1)$

Correct upto six decimal places.

Now,

$\lim_{x\to 0}F(x)=\lim_{x\to 0}\frac{e^x-1-x}{x^2}$ $(\frac{0}{0})$ form, applying L-Hospital rule that is differentiating numerator and denominator we get,

$\lim_{x\to 0}F(x)$

$=\lim_{x\to 0}\frac{e^x-1}{2x}$ $(\frac{0}{0})$ form.

$=\lim_{x\to 0}\frac{e^x}{2}=\frac{1}{2}=0.5\hfill (2)$

Limit exist and is 0.5. That is according to (1) we can see as the value of x lesser than 1 and tending to near 0, value of the function decreases respectively. And from (2) it shows ultimately it decreases and reach at 0.5, consider as limit point of F(x).

8 0

3 years ago

Adante begins to evaluate the expression 3 1/3 x 5 1/4 using the steps below

il63 [147K]

Answer:

$\frac{35}{2}$