If

represent a family of surfaces for different values of the constant

. The gradient of the function

defined as

is a vector normal to the surface

.
Given <span>the paraboloid

.
We can rewrite it as a scalar value function f as follows:

The normal to the </span><span>paraboloid at any point is given by:

Also, the normal to the given plane

is given by:

Equating the two normal vectors, we have:
</span>

Since, -1 = 2 is not possible, therefore
there exist no such point <span>
on the paraboloid
such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2</span>
.
Answer:
Step-by-step explanation:
Given:
AB ≅ BC
AK ≅ KC
∠AKE ≅ ∠CKP
To Prove:
ΔAKE ≅ ΔCKP
Statements Reasons
1). AB ≅ BC 1). Given
2). ∠BAC ≅ ∠BCA 2). Property of Isosceles triangles
3). ∠EKA ≅ ∠PKC 3). Given
4). ΔAKE ≅ ΔCKP 4). ASA Postulate of congruence
Hence ΔAKE ≅ ΔCKP.
Answer:
A.
x + y = 28
1.68x + 2.44y = 54.64
Step-by-step explanation:
Let x = paperback books and y = hardback books
x+y =28
We know that paperbacks cost 1.68 and hardback cost 2.44
1.68x + 2.44y = 54.64
We have 2 equations and 2 unknowns
x+y =28
1.68x + 2.44y = 54.64
Answer:
x.
Step-by-step explanation:
If h(x) is the inverse of f(x) them h(f(x)) = x.