According to the given information, the equation represents a line that is tangent to the circle and goes through the point W is given by:
y = -x + 6.
<h3>What is the equation of the circle?</h3>
The equation of a circle of center 
and radius r is given by:
In this problem, we have that the center is at point (0,2), hence:
It goes through point (3,3), hence:
Hence, the equation is:
<h3>What is the equation of the tangent line at point W?</h3>
It is given by:
Applying implicit differentiation, we have that:
Point W(3,3), hence:
Hence the equation is:
y - 3 = -(x - 3).
y = -x + 6.
More can be learned about the equation of a tangent line at brainly.com/question/8174665
A^2-b^2=(a+b)(a-b)
1: x^2-4=(x+2)(x-2)
2: (x+8)(x-8)
3: (x+10)(x-10)
4: (x+14)(x-14)
6.1.8 The following set of scores was obtained from a quiz: 4, 5, 8, 9, 11, 13, 15, 18, 18, 18, 20. The teacher computes the usu
Inessa05 [86]
Answer:
B. Median
D. IQ R
Step-by-step explanation:
from the given data :
mean = 12.6364 , median =13,
st. dev = 5.6262
Q3 = 18 , Q1 = 8
IQ R = Q3 - Q1 = 18-8 = 10
One of the 18s should be 16 then,
mean = 12.4545, median = 13,
st. dev = 5.4656
Q3 = 18 , Q1 = 8
IQ R = Q3 - Q1 = 18-8 = 10
So, median and IQ R will not need to be changed
For any point reflected in the y- axis
(x, y ) → (- x, y )
A(1, 1) → A'(- 1, 1)
B(5, 1 ) → B'(- 5, 1 )
C(3, 3 ) → C'(- 3, 3 )
