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KengaRu [80]
3 years ago
15

Find the value of x (3/5)^x(5/3)^2x=125/27​

Mathematics
1 answer:
lesya692 [45]3 years ago
8 0

Given:

The equation is

\left(\dfrac{3}{5}\right)^x\left(\dfrac{5}{3}\right)^{2x}=\dfrac{125}{27}

To find:

The value of x.

Solution:

We have,

\left(\dfrac{3}{5}\right)^x\left(\dfrac{5}{3}\right)^{2x}=\dfrac{125}{27}

\left(\dfrac{5}{3}\right)^{-x}\left(\dfrac{5}{3}\right)^{2x}=\dfrac{5\times 5\times 5}{3\times 3\times 3}      [\because \left(\dfrac{a}{b}\right)^{-m}=\left(\dfrac{b}{a}\right)^{m}]

\left(\dfrac{5}{3}\right)^{-x+2x}=\dfrac{5^3}{3^3}          [\because a^ma^n=a^{m+n}]

\left(\dfrac{5}{3}\right)^{x}=\left(\dfrac{5}{3}\right)^{3}

On comparing the exponents, we get

x=3

Therefore, the value of x is 3.

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Answer:

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The vertex is (-\frac{7}{2},-\frac{53}{4})

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f(x) = (x+\frac{b}{2})^2 +k

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The vertex is (-\frac{7}{2},-\frac{53}{4})

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