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IgorLugansk [536]
3 years ago
5

Please someone help me!! Look at picture. Also write as it expression.

Mathematics
1 answer:
Fynjy0 [20]3 years ago
6 0

Answer:hi there!that same guy did that w my question too :( i’m reporting his answers. i will help u out tho ahah. the answer is 470(32-n). i hope this helps :). have a good dayyy

Step-by-step explanation:

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Find all the zeros of the equation
lapo4ka [179]

Divide both sides by -3, and replace x^2 with y. Then

-3x^4+27x^2+1200=0\iff y^2-9y-400=0

Factorize the quadratic in y to get

y^2-9y-400=(y+16)(y-25)=0\implies y=-16,y=25

which in turn means

x^2=-16,x^2=25

But x^2\ge0 for all real x, so we can ignore the first solution. This leaves us with

x^2=25\implies x=\pm\sqrt{25}=\pm5

If we allow for any complex solution, then we can continue with the solution we ignored:

x^2=-16\implies x=\pm\sqrt{-16}=\pm i\sqrt{16}=\pm4i

6 0
3 years ago
Please help with 4-9!!!
olya-2409 [2.1K]

sdfsdf

4) \frac{3m+15}{2} = 22.5

Multiply by 2 on both sides

3m + 15 = 45

Subtract both sides by 15

3m = 30

Divide both sides by 3

so m = 3

5) 21= \frac{q+35}{8}

Multiply both sides by 8

168 = q + 35

Subtract both sides by 35

q = 133

6) 14 + \frac{4z}{-11} = 66

Subtract 14 from both sides

\frac{4z}{-11} = 52

multiply by -11 on both sides

4x = 572

Divide both sides by 4

x= 143

7) \frac{3}{5} c - 6 = 9

Add 6 on both sides

\frac{3}{5} c  = 15

Multiply both sides by 5

3c = 75

Divide both sides by 3

c = 25

8) \frac{t}{-2} + 17 = -9

Subtract both sides by 17

\frac{t}{-2} =26

Multiply both sides by -2

t = -52

9) -6 = \frac{5p-(-2)}{-7}

Multiply both sides by -7

42= 5p + 2

subtract 2 from both sides

40 = 5p

Divide both sides by 5

so p = 8






6 0
3 years ago
Read 2 more answers
What is the median of the following data values 98,102,53,80,22
timurjin [86]

Answer:

80

Step-by-step explanation:

8 0
3 years ago
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What is the length of AB?<br> 14 unite<br> 12 unite<br> 10 unite<br> 6 units
Sloan [31]

the answer willllll be 6 units

5 0
2 years ago
6. Fill in the smallest digit to make the number divisible by:
Degger [83]

Answer:

(i) 7164<u>0</u>, 32197<u>0</u>

(ii) 1<u>1</u>43, 47<u>2</u>05, <u>2</u>316

(iii) <u>1</u>428, 9<u>2</u>52, 721<u>2</u>

(iv) 2462<u>0</u>, 91<u>00</u>, 670<u>0</u>

(v) 1232<u>0</u>, 59<u>0</u>16, 4642<u>4</u>

Step-by-step explanation:

(i) In order for any number to be divisible by 5, its last digit must be <u>either 0 or 5</u>.

In this case, we should add a last digit, so we opt for <u>0</u> without any doubt since it gives a smaller number than <u>5</u> as the last digit: 71640 is smaller than 71645, the same way as 321970 is smaller than our second option, 321975.

(ii) If the sum of a number's digits gives a number divisible by 3, then the main number is also divisible by 3.

This means that we have to do some addition:

1_43: 1 + 4 + 3 = 8. Eight is not divisible by 3. But <u>9</u> is. So the smallest digit we can add for it to be divisible by three is <u>1</u>: <em>1143.</em>

47_05: 4 + 7 + 0 + 5 = 16. Since 16 is not, the next number that is divisible by 3 is 18, and therefore, the smallest digit we need here is <u>2</u>: <em>47205.</em>

_316: 3 + 1 + 6 = 10. Twelve is the next number divisible by 3, and that means <u>2</u> is the digit we choose: <em>2316.</em>

(iii) Only numbers that are divisible by both <u>2 and 3</u> are also divisible by 6.

_428: In order for a number to be divisible by 2, its last digit must be 0 or divisible by 2. That is already the case here.

4 + 2 + 8 = 14 which is not divisible by 3. But 15 is. So the smallest digit we need is <u>1</u>: <em>1428.</em>

9_52: The number will be divisible by 2. And 9 + 5 + 2 = 16 which is not divisible by 3 but 18 is. This means the smallest digit we need is <u>2</u>: <em>9252.</em>

721_: Since the last digit can be any of these <u>0, 2, 4, 6, 8</u> for the number to be divisible by two, we will first see what digit we need for it to be divisible by 3.

7 + 2 + 1 = 10 which is not divisible by 3 but 12 is. We will then choose to add <u>2</u>: <em>7212.</em>

(iv) A number is divisible by 4 only if the number that is formed by its two last digits is also divisible by 4..

2462_: Since we need to add a last digit, this should be easy. The smallest two-digit-number that starts with 2 and is divisible by four is <u>20</u>: <em>24620. </em>

91__: Here we need to add both of the two last digits, and this should be the easiest example! All numbers that end in <u>00</u>, meaning they have a round number of hundreds, are divisible by 4! Therefore our option is: <em>9100.</em>

670_: In this case, we apply the same rule from the last example - and we choose <u>0</u>: <em>6700.</em>

(v) In order for a number to be divisible by 8, its last three digits need to be divisible by 8, or it can end in <u>000,</u> since every number having a round number of thousands is also divisible by 8.

1232_: 320 is divisible by 8 since 8 × 40 gives 320. Therefore, our smallest digit here is <u>0</u>: <em>12320.</em>

59_16: If we add a <u>0</u> here, the last three digits form the number 016, which is divisible by 8. Our choice is again zero: <em>59016.</em>

4642_: Unfortunately, 420 is not divisible by 8. The next number closest to 420 and which is divisible by 8 is 424. Its division by 8 gives 53. Therefore we should add <u>4</u>: <em>46424.</em>

7 0
2 years ago
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