This is the concept of geometry, given that AB=AC, it means that the tirangle is isosceles, thus to get the value of AB and AC we proceed as follows;
thus using the cosine rule:
c^2=a^2+b^2-2abcosC
suppose\AB=AC=x
thus;
8^2=x^2+x^2-2*x*xcos15
64=2x^2-2x^2cos15
64=2x^2-1.9x^2
64=0.1x^2
x^2=640
x=sqrt640
x=25.3
hence;
AC=AB=25.3
Answer:
Step-by-step explanation:
The remainder when p(x) is divided by (x+2) is; -79.
<h3>What is the remainder when p(X) is divided by (X+1)?</h3>
Since one of it's factors is (x+1), it follows that P(-1) = 0.
Hence; 0 = (-1)³ -4(-1)² -a +20
a = 15.
Hence, the polynomial is; p(x)=x3−4x2+15x+20
The remainder when p(x) is divided by (x+2) is;
p(-2) = (-2)³ -4(-2)² + 15(-5) +20
p(-2) = -8 -16 -75 +20
p(-2) = -79.
Read more on remainder theorem;
brainly.com/question/15165392
#SPJ1
CP of pen = ₹20
Profit % = 20%
Profit % = profit × 100 / CP
20 = profit × 100 / 20
20 × 20 / 100 = profit
Profit = ₹4
Profit = SP - CP
4 = SP - 20
SP = ₹24
Let new CP be ₹x
Profit % = 25%
SP = ₹24
Profit % = SP - CP
25x / 100 = 24 - x
24x / 100 + x = 24
125x / 100 = 24
5x / 4 = 24
x = 24 × 4 / 5
x = ₹ 19.20