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2 years ago

Real numbers are always rational numbers

Mathematics

1 answer:

DiKsa [7]2 years ago

8 0

Yes, real numbers are always rational numbers

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Which Statement is true ?

elena55 [62]

F(-4)=G(-4) because when the two lines cross over the f line is at the -4 and same with G

7 0

2 years ago

Rob needs to mix 4.5 liters of liquid fruit punch concentrate with 0.5

Dmitriy789 [7]

4.5 litres of fruit punch with 0.5 litres of water.
13.5 /4.5 = 3. Multiply 0.5 by 3 to get 1.5 litres of water. Therefore, 13.5 litres of fruit punch concentrate needs 1.5 litres of water. 13.5 + 1.5 = 15 litres of fruit punch in total.

7 0

1 year ago

What is each power of i with its multiplicative inverse.

pentagon [3]

Answer:

1) multiplicative inverse of i = -i

2) Multiplicative inverse of i^2 = -1

3) Multiplicative inverse of i^3 = i

4) Multiplicative inverse of i^4 = 1

Step-by-step explanation:

We have to find multiplicative inverse of each of the following.

1) i

The multiplicative inverse is 1/i

if i is in the denominator we find their conjugate

$=1/i * i/i\\=i/i^2\\=We\,\, know\,\, that\,\, i^2 = -1\\=i/(-1)\\= -i$

So, multiplicative inverse of i = -i

2) i^2

The multiplicative inverse is 1/i^2

We know that i^2 = -1

1/-1 = -1

so, Multiplicative inverse of i^2 = -1

3) i^3

The multiplicative inverse is 1/i^3

We know that i^2 = -1

and i^3 = i.i^2

$1/i^3\\=1/i.i^2 \\=1/i(-1)\\=-1/i * i/i\\=-i/i^2\\= -i/-1\\= i$

so, Multiplicative inverse of i^3 = i

4) i^4

The multiplicative inverse is 1/i^4

We know that i^2 = -1

and i^4 = i^2.i^2

$=1/i^2.i^2\\=1/(-1)(-1)\\=1/1\\=1$

so, Multiplicative inverse of i^4 = 1

3 0

2 years ago

Determine a series of transformations that would map polygon ABCDE onto polygon A’B’C’D’E

zalisa [80]

Answer:

Reflected across x-axis followed by a dilation with a scale factor of 2 about the origin.

Step-by-step explanation:

It's clear from the graph,

Polygon ABCDE is reflected across x-axis then dilated so that it overlaps polygon A'B'C'D'E'

Let's choose a point A having coordinates (-2, -1)

By reflecting point A across x-axis,

Rule to be followed for the reflection,

(x, y) → (x, -y)

By this rule, coordinates of the image point A will be,

A(-2, -1) → A"(-2, 1)

Now point A"(-2, 1) has been dilated by a scale factor = k to form an image points A'(-4, 2).

Rule for the dilation of a point about the origin is,

A"(x, y) → A'(kx, ky)

A"(-2, 1) → A'(-2k, k)

Since, coordinates of point A' are (-4, -2),

Therefore, -2k = -4

k = 2

Hence, polygon ABCDE was reflected across x-axis followed by a dilation with a scale factor of 2 about the origin to form polygon A'B'C'D'E'.

3 0

2 years ago

-4(1 -6b) - 5 ( 2b - 6)= 8b - 7b

Citrus2011 [14]

The answer is b=-2 Hope that helps!!

5 0

2 years ago

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