<h3>
Answer: -√46 is between -7 and -6</h3>
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Explanation:
List out the perfect squares
- 1^2 = 1
- 2^2 = 4
- 3^3 = 9
- 4^2 = 16
- 5^2 = 25
- 6^2 = 36
- 7^2 = 49
- 8^2 = 64
and so on. We can see that 46 is between 6^2 = 36 and 7^2 = 49.
We can say 6^2 < 46 < 7^2
Applying the square root to all three sides leads us to 6 < sqrt(46) < 7
Now multiply all three sides by -1. This will flip the inequality signs
We go from
6 < sqrt(46) < 7
to
-6 > -sqrt(46) > -7
It might help to order things from smallest to largest to get this
-7 < -sqrt(46) < -6
This means -sqrt(46) is between -7 and -6 on the number line
See the diagram below.
Answer:
B
Step-by-step explanation:
yes, we need two numbers that multiplied with each other results in -48.
that means already that one of them has to be positive and the other negative.
that gives us (with all +/- alternating sign combinations)
2 and 24
3 and 16
4 and 12
6 and 8
to pick from there we see that the "middle" term is -2x.
that means that the absolute value of the negative number has to be 2 more than the positive number (so that when adding the intermediate multiplication terms we end up with -2x).
the only choice is therefore 6 and -8.
and that makes B the right answer.
because the x values are identical the radius would be found by subtracting the y values.
6-2 = 4
the radius is 4
Answer:
42°, 101°
Step-by-step explanation:
These answers come from the angle subtraction postulate.
Solution :
Consider quadrilateral ABCD is a parallelogram. The parallelogram have diagonals AC and DB.
So in the given quadrilateral ABCD, let the diagonal AC and diagonal DB intersects at a point E.
Thus in the quadrilateral ABCD we see that :
1. AC and DB are the diagonals of quadrilateral ABCD.
2. Angle DCE is congruent to angle BAE and angle CDE is congruent to angle ABE. (they are alternate interior angles)
3. Line DC is congruent to line AB. (opposites sides are congruent in a parallelogram )
4. Angle ABE is congruent to angle CDE. (Angle side angle)
5. Line AE is congruent to line EC. And line DE is congruent to line EB. (CPCTC)
Thus we see that if the diagonals of a 
, then the quadrilateral is a parallelogram.
