Pls help it has to do with a cube

If −5e^x^2 y=x and y(−5)=0, find y′(−5) by implicit differentiation

xenn [34]

Differentiate:
-5×2(xe^x^2)y-5e^x^2dy/dx=1
-5e^x^2(2xy+y´)=1
When x=-5, y=0:
-5e²⁵y´=1, so y´(-5)=-eˉ²⁵/5

6 0

2 years ago

Tina covers the floor of a room with carpeting. She uses carpet squares that measure one foot on each side. How many carpet squa

gizmo_the_mogwai [7]

Answer:

She need 96 square feet carpet to cover the room.

Step-by-step explanation:

Given:

Tina covers the floor of a room with carpeting. She uses carpet squares that measure one foot on each side.

Now, to find carpet squares does she need to cover a room that 8 feet wide by 12 feet long.

So, the dimensions of room are:

Length = 12 feet.

Width = 8 feet.

Now, getting the area by putting formula:

Area of room = Length × width

$Area\ of\ room = 12\times 8$

$Area\ of\ room=96\ square\ feet.$

Therefore, she need 96 square feet carpet to cover the room.

3 0

2 years ago

Prove usin's Mathematical induction 2^n ≤(n+1)!, for n≥0

Westkost [7]

Answer:

Step-by-step explanation:

2^0 is less than or equal to 1!, because 1<= 1

if 2^n <= (n+1)!, we wish to show that 2^(n+1) <= (n+2)!, since

(n+2)! = (n+1)! * (n+2), and (n+1)!>= 2^n, then we want to prove that n+2<=2, which is always true for n>=0

8 0

1 year ago

Write a function rule for the relationship. the amount c of energy you burn and the time t you spend exercising, if you burn Cal

gregori [183]

Answer:

c= 12t

c is the amount of energy you burn, so it'll be the "solution" to the equation. Multiply 12 times the amount of time you spend exercising to find how much energy you'll burn.

6 0

3 years ago

Which equation represents a proportional relationship? A. y = x + 1 3 y=x+13 B. y = 1 − 1 3 x y=1-13x C. y = 3 x + 1 3 y=3x+13 D

34kurt

Answer:

Option D. $y=\frac{1}{3}x$

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

Verify each case

case A) we have

$y=x+\frac{1}{3}$

Remember that

the line must pass through the origin

so

For x=0, y=0

In this case

For x=0

$y=0+\frac{1}{3}=\frac{1}{3}$

so

The line not passes through the origin

therefore

The equation A not represent a proportional relationship

case B) we have

$y=1-\frac{1}{3}x$

Remember that

the line must pass through the origin

so

For x=0, y=0

In this case

For x=0

$y=1-\frac{1}{3}(0)=1$

so

The line not passes through the origin

therefore

The equation B not represent a proportional relationship

case C) we have

$y=3x+\frac{1}{3}$

Remember that

the line must pass through the origin

so

For x=0, y=0

In this case

For x=0

$y=3(0)+\frac{1}{3}=\frac{1}{3}$

so

The line not passes through the origin

therefore

The equation C not represent a proportional relationship

case D) we have

$y=\frac{1}{3}x$

Remember that

the line must pass through the origin

so

For x=0, y=0

In this case

For x=0

$y=\frac{1}{3}(0)=0$

so

The line passes through the origin

therefore

The equation D represent a proportional relationship

3 0

3 years ago