Answer:
0.3431
Step-by-step explanation:
Here, it can work well to consider the seeds from the group of 18 that are NOT selected to be part of the group of 15 that are planted.
There are 18C3 = 816 ways to choose 3 seeds from 18 NOT to plant.
We are interested in the number of ways exactly one of the 10 parsley seeds can be chosen NOT to plant. For each of the 10C1 = 10 ways we can ignore exactly 1 parsley seed, there are also 8C2 = 28 ways to ignore two non-parsley seeds from the 8 that are non-parsley seeds.
That is, there are 10×28 = 280 ways to choose to ignore 1 parsley seed and 2 non-parsley seeds.
So, the probability of interest is 280/816 ≈ 0.3431.
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The notation nCk is used to represent the expression n!/(k!(n-k)!), the number of ways k objects can be chosen from a group of n. It can be pronounced "n choose k".
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Okay hold on. I’m trying to figure this question out. I will help you!
The First group i.e 1-10 include more prime numbers .(2,3,5,7,1)
- Because it has the basic inputs of every number
- Like 15 consists of 3×5
4. SOLVE FOR X:
Using the Alternate Interior Angles Theorem, we know that the 67 degree angle is congruent with the (12x - 5) degree angle. With this information, all I have to do is set the two equal to each other and solve for x.
67 = 12x - 5
67 + 5 = 12x - 5 + 5
72/12 = 12x/12
6 = x
x = 6
SOLVE FOR Y:
Using the Vertical Angles theorem, we know that angle y must be congruent to the 67 degree angle.
y = 67 degrees.
5. SOLVE FOR Y:
Alternate exterior angles: 6(x - 12) = 120
6x - 72 + 72 = 120 + 72
6x/6 = 192/6
x = 32
SOLVE FOR Y:
6((32) - 12) + y = 180
192 - 72 + y = 180
120 + y - 120 = 180 - 120
y = 60