Answer:
After 4 weeks they have $413
After 5 weeks they have $485 (more than enough money)
Step-by-step explanation:
we know that here are 3 people saving up this money and we know that they have already saved 125 dollars.
if each saves $24 per week... 24*3=72 (total profit per week)
for 4 weeks... 72*4=288
288+125(already saved up)= 413
If they go one more week and save up another 72 dollars in 1 week this will bring them past their goal
Answer:
<em>5 boys play all the two games</em>
<em>25 boys play only one game</em>
Step-by-step explanation:
<u>Sets</u>
There are two sets defined in the question: one for the boys who play hockey (H) and the other for the boys who play volleyball (V).
All the boys play at least one of the two games, so no elements are outside both sets.
There are 30 boys in total. 20 of them play hockey and 15 play volleyball. Since the sum of both numbers is greater than the total of boys, the difference corresponds to the boys who play both games.
Thus 20 + 15 - 30 = 5 boys play both games
Given that 5 boys are shared by both sets, from the 20 playing hockey, 15 play ONLY hockey. From the 15 boys playing volleyball, 10 play ONLY volleyball.
Thus 15 + 10 = 25 boys play only one game.
The Venn diagram is shown in the image.
Here is the answer to the given problem above.
Here is the exponential function to model this situation:
<span>f(x) = 420(0.79)x
Now, solve with the given values.
</span><span>P(t)=420×(.79<span>)^t</span></span>
<span><span>P(5)=420×(.79<span>)^5</span>=129
So the answer would be 129 animals.
Hope this answer helps. Thanks for posting your question!</span></span>
Answer:
15 hope it helps:)
Step-by-step explanation:
because it divides 5 in each side
The vertical asymptotes are: "
x = 3" and "
x = -3" .
__________________________________________The horizontal asymptote is: "
y = 2" .
___________________________________________Explanation:___________________________________________f(x) =

;
We know that "(x² − 9) ≠ 0 ; since we cannot divide by "0" ; so the "denominator" in the fraction cannot be "0" ;
since: 9 − 9 = 0 ; "x² " cannot equal 9.
So, what values for "x" exist when "x = 9" ?
x² = 9 ;
Take the square root of EACH SIDE of the equation ; to isolate "x" on one side of the <span>equation ; and</span> to solve for "x" ;
√(x²) = √9 ;
x = ± 3
<span>
__________________________________________So; the vertical asymptotes are: "x = 3" and "x = -3" .
__________________________________________The horizontal asymptote is: "y = 2" .
__________________________________________(since: We have: </span>f(x) =

;
The "x² / x² " as the highest degree polymonials; both with "implied" coefficients of "1" ; and both raised to the same exponential power of "2".