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Firdavs [7]
2 years ago
7

PLEASE ASAP I NEED HELP ON THIS PROBLEM

Mathematics
1 answer:
Nitella [24]2 years ago
7 0

Answer: to be true  I don't understand this

Step-by-step explanation:

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Graph f(x)=−0.5x+3. Use the line tool and select two points to graph the line.
NikAS [45]

Answer: These are some points of the grahp:

(-2,4)

(0, 3)

(2, 2)


Explanation:


1) f(x) =  -0.5x + 3, is the equation of the form y = mx + b


2) y = mx + b is slope-intercept  equation of a line where the slope is m and the y-intercept is b, so, f(x) = - 0.5x + b has slope m = -0.5 and y-intercept b = 3.


3) To graph f(x) = -0.5x + 3, follow these steps:

  • draw two perpedicular axis: vertical axis, labeled y, and horizontal axis, labeled x.
  • draw marks on each axis, each mark equivalent to one unit.
  • the intersection point of the vertical and horizontal axis is the origin, i.e. point (0,0).
  • you can make a table with two or more points:

        x       f(x) = - 0.5x + 3

        -2         4

        0          3

        2          2

        4           1

        6          0


4) You can see the graph in the figure attached, and select any of the points on the line either by using the table or by using the equation f(x) = -0.5x + 3.

8 0
3 years ago
Read 2 more answers
Find the equation of a line that passes through the point (5,2) and has a gradient of 2. Leave your answer in the form y = m x +
WINSTONCH [101]

good luck!!... hope it help! :)

5 0
2 years ago
Read 2 more answers
I need help, what is 9^-2+181-69? this is math
satela [25.4K]

Answer:

193

Step-by-step explanation:

9^2 = 81+181=262-69= 193

4 0
2 years ago
What is the solution of the equation? Eliminate any extraneous solutions √3x + 28 - 8 = x
Alecsey [184]
The answer to the solution is x=43+√249/2

I hope this helps.
6 0
3 years ago
Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.
Mice21 [21]

Answer:

<em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

Step-by-step explanation:

Making factors of 8y^{6}+ 144y^{5}+ 640y^{4}

Taking 8y^{4} common:

\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)

Using <em>factorization</em> method:

\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times  4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)

Now, Making factors of 2y^{4} + 40y^{3} + 200y^{2}

Taking 2y^{2} common:

\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)

Using <em>factorization</em> method:

\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10)        ............ (2)

The underlined parts show the Highest Common Factor(HCF).

i.e. <em>HCF</em> is 2y^{2} (y+ 10).

We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

HCF \times LCM = p \times q

Using equations <em>(1)</em> and <em>(2)</em>: \Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)

Hence, <em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

5 0
3 years ago
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