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Dimas [21]
3 years ago
11

Heeelllllllllpppppppp meeeeee

Mathematics
2 answers:
Alenkasestr [34]3 years ago
6 0

Answer:

32

Step-by-step explanation:

36-4

Use Pythagorean theorem

vagabundo [1.1K]3 years ago
6 0

Answer:

B=4

Step-by-step explanation:

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Ruby weighs 88 lbs. Her weight is 12 lbs. less than half her mother's weight. How much does her mother weigh?
GenaCL600 [577]

88 = m - 12

<u>+ 12       + 12</u>

100 = m

8 0
3 years ago
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Write the equation of the line given the slope and a point through the line passes
Anuta_ua [19.1K]

Answer:

1.) Y = 5/3 X + 4

2.) Y = 9/4 X - 27/4

Step-by-step explanation:

Given the slope and the coordinate, linear equation of a line can be expressed by using general linear equation. Which is

Y = MX + C

Where the

Slope M = 5/3

Coordinate = (-3,-1) in which

X = -3, Y = -1

Substitute X, Y and M into the general linear equation to achieve C

-1 = 5/3(-3) + C

-1 = - 5 + C

C = 5 - 1

C = 4

Substitute C and M back into the general linear equation.

Therefore, the equation of the line given the slope and a point through the line passes 5/3, and (-3,-1) to be

Y = 5/3 X + 4

2.) Also,

Slope M = 9/4

Coordinate = (3,0) where X = 3, Y = 0

Substitute X, Y and M into the general linear equation to obtain C

0 = 9/4 (3) + C

C = - 27/4

Substitutes C and M back into the general linear equation

Therefore, the equation of the line given the slope and a point through the line passes 9/4 and (3,0)

Y = 9/4 X - 27/4

4 0
3 years ago
Eva Maria borrowed money from her father and agreed to pay him 4% simple annual interest. At the end of 7 years, Eva Maria owes
zaharov [31]

4% simple interest after 7 years is 28% interest.

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A right pyramid with a regular hexagon base has a height of 3 units If a side of the hexagon is 6 units long, then the apothem i
Setler79 [48]

Answer:

Part a) The slant height is 3\sqrt{2}\ units

Part b) The lateral area is equal to 54\sqrt{2}\ units^{2}

Step-by-step explanation:

we know that

The lateral area of a right pyramid with a regular hexagon base is equal to the area of its six triangular faces

so

LA=6[\frac{1}{2}(b)(l)]

where

b is the length side of the hexagon

l is the slant height of the pyramid

Part a) Find the slant height l

Applying the Pythagoras Theorem

l^{2}=h^{2} +a^{2}

where

h is the height of the pyramid

a is the apothem

we have

h=3\ units

a=3\ units

substitute

l^{2}=3^{2} +3^{2}

l^{2}=18

l=3\sqrt{2}\ units

Part b) Find the lateral area

LA=6[\frac{1}{2}(b)(l)]

we have

b=6\ units

l=3\sqrt{2}\ units

substitute the values

LA=6[\frac{1}{2}(6)(3\sqrt{2})]=54\sqrt{2}\ units^{2}

3 0
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Number 21 would be 6 39/40
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