Answer:
The correct answer is D! Hope this helps!
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For this, you need to use Punnett squares.
You know the genotype of the parents, and for the cross, you need to separate into two alleles, both genes.
AABBCc divided like ABC and ABc.
Aabbcc divided like Abc and abc.
Now you can cross them, and all probabilities will be:
AABbCc, AaBbCc, AABbcc and AaBbcc
So, you could say 25% of the offspring will be AaBbCc, 25% AaBbcc, 25% AABbCc, and 25% AABbcc
The disorder can occur anytime
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