The vertex will be when the velocity is equal to zero:
df/dx=-12x+24 (using the power rule for differentiation)
df/dx=0 only when:
-12x+24=0 add 12x to both sides
12x=24 divide both sides by 12
x=2, we find the y value to be:
y(2)=-6(2^2)+24*2-20
y(2)=-24+48-20=4
So the vertex is the point (2,4)
And the axis of symmetry is the line x=2
Now if you do not yet do calculus...
The vertex will occur midway between the two zeros.
6x^2-24x+20=0 (using the Quadratic Formula for simplicity)
x=(24±√96)/12
x≈(1.1835, 2.8165)
Now the vertex occurs at the average of the zeros...
x=(1.1835+2.8165)/2=2 (as we saw earlier)
y(2)=4
Vertex is at (2,4) and axis of symmetry is the vertical line x=2
Answer:
96
Step-by-step explanation:
24/ (1 - 3/4)
24 / (1/4)
24 x 4 = 96
Answer:
4
Step-by-step explanation:
Answer:
0.07x - 0.002x^2 - 0.3
Step-by-step explanation:
Given the expression shown (0.2x-1)+(0.3-0.01x)
Expand
(0.2x-1)+(0.3-0.01x)
= 0.2x(0.3) - 0.2x(0.01x)-1(0.3) + 1(0.01x)
= 0.06x - 0.002x^2 - 0.3 + 0.01x
= 0.06x+0.01x - 0.002x^2 - 0.3
= 0.07x - 0.002x^2 - 0.3
This gives the required expression
Answer:
y = 0
Step-by-step explanation:
Given
4y + 12 = 6y + 12 ( subtract 6y from both sides )
- 2y + 12 = 12 ( subtract 12 from both sides )
- 2y = 0, hence
y = 0
