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yan [13]
3 years ago
7

Hello please answer ASAP i will give brainliest.

Mathematics
2 answers:
castortr0y [4]3 years ago
8 0
Answer:B

Explanation:
iragen [17]3 years ago
7 0

Answer:

B

Step-by-step explanation:

There is a pattern. Subtract input from output and it is 11. So, if 11 is the pattern. subtract 51 from A,B,C, and D.Till one of them has the number 11 as answer. 51- 40=11. 40 = B

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A user’s password to access a computer system consists of 3 letters followed by 2 digits. How many different passwords are possi
Vesnalui [34]

Answer:

26*26*26 = 17576 ways to select 3 letters

10*10= 100 ways to select 2 numbers

So then the total number of ways are:

26^3 *10^2 = 1757600 possible ways

Step-by-step explanation:

For this case we assume that we have 26 letters from A to Z and 10 numbers from 0 to 9 .

And we want to calculate the number of possible passwords possible if the password consists of 3 letters followed by 2 digits.

And for this case we can use the multiplication principle of combinatories, since we don't have any restriction about the letters of the numbers we can have repetition of letters or numbers.

For the number of possible letters:

26*26*26 = 17576 ways to select 3 letters

10*10= 100 ways to select 2 numbers

So then the total number of ways are:

26^3 *10^2 = 1757600 possible ways

7 0
3 years ago
Read 2 more answers
Is 3/10 equivalent to 2/5 please tell me the right answer
aev [14]
3 divided by 10 is 0.3

2 divided by 5 is 0.4.

They are not equivalent.
8 0
3 years ago
An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
3 years ago
Simplify (3+√5)(3+√2)
ANEK [815]

When we simplify (3 + √5)(3 + √2), the result obtained is:

9 + 3√2 + 3√5 + √10

<h3>Surd operation </h3>

a√b × c√d = (a × c)√(b × d)

<h3>How to simplify (3 + √5)(3 + √2)</h3>

(3 + √5)(3 + √2)

Expand by clearing the bracket

3(3 + √2) + √5(3 + √2)

9 + 3√2 + 3√5 + √10

Thus,

(3 + √5)(3 + √2) = 9 + 3√2 + 3√5 + √10

Learn more about surd:

brainly.com/question/24700530

#SPJ1

3 0
2 years ago
At a dog park , there are 10 black dogs, 5 brown dog, 2 white dog, and 12 multi color dogs​
Sophie [7]
What question are you trying to ask?
5 0
3 years ago
Read 2 more answers
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