Given:
The expression is:
To find:
The integration of the given expression.
Solution:
We need to find the integration of .
Let us consider,
![[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]](https://tex.z-dn.net/?f=%5B%5Cbecause%201%2B%5Ccos%202x%3D2%5Ccos%5E2x%2C1-%5Ccos%202x%3D2%5Csin%5E2x%5D)
![\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Ctan%20%5Ctheta%20%3D%5Cdfrac%7B%5Csin%20%5Ctheta%7D%7B%5Ccos%20%5Ctheta%7D%5Cright%5D)
It can be written as:
![[\because 1+\tan^2 \theta =\sec^2 \theta]](https://tex.z-dn.net/?f=%5B%5Cbecause%201%2B%5Ctan%5E2%20%5Ctheta%20%3D%5Csec%5E2%20%5Ctheta%5D)
Therefore, the integration of is .
A = {1, 3, 5, 7, 9} B = {2, 4, 6, 8, 10} C = {1, 5, 6, 7, 9} A ∩ (B ∪ C) =
vovikov84 [41]
A = {1, 3, 5, 7, 9}
B = {2, 4, 6, 8, 10}
C = {1, 5, 6, 7, 9}
(B ∪ C) = {1, 2, 4, 5, 6, 7, 8, 9, 10}
so
A ∩ (B ∪ C) = {1, 5, 7 , 9}
Answer:
you need to provide a picture friend
Answer:
sorry if im wrong i think wrong numbers. plz check
Step-by-step explanation:
The center of dilation of the question is (-4,-3) .
let say that
x0=-4
y0=-3
Label the image A'B'C'
The new coordinate would be
A(-4,-1)
x=4
y=-1
x'=x0+ 2(x - x0)
x'= -4+ 2(-4 +4)
x'=-4
y'=y0+ 2(y - y0)
y'= -3+ 2(-1 +3)
y'=-3 +4= 1
______________________________
B(-4,-3)
x=-4
y=-3
x'=x0+ 2(x - x0)
x'= -4+ 2(-4 +4)
x'=-4
y'=y0+ 2(y - y0)
y'= -3+ 2(-3 +3)
y'=-3
______________________________
C(-1,-3)
x=-1
y=-3
x'=x0+ 2(x - x0)
x'= -4+ 2(-1 +4)
x'=-4 +6= 2
y'=y0+ 2(y - y0)
y'= -3+ 2(-3 +3)
y'=-3
A'(-4,1)
B'(-4,-3)
C'(2,-3)
Answer:
4
Step-by-step explanation:
y=mx+c,m(4) is the slope
