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valentinak56 [21]
2 years ago
6

Help!!1! please solve this it was due yesterday and i have school in 2 hrs

Mathematics
1 answer:
LuckyWell [14K]2 years ago
5 0
Probably 6.4 pounds not sure
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What is the value of d/dx (6/x^4 + 1/x^2) at x = -1 ?
zheka24 [161]

Answer:

\frac{d}{dx}\left(\frac{1+x^4+x^6}{x^2+x+1}\right)=\frac{4x^7+5x^6+8x^5+3x^4+4x^3-2x-1}{\left(x^2+x+1\right)^2}

Step-by-step explanation:

7 0
3 years ago
Your answer should be a polynomial in standard form (x-2)(x-1)= ?
fredd [130]
The answer is x squared -3x+2
6 0
3 years ago
4x-y=10 and y=2x-2 answers
Brums [2.3K]
4x - y = 10, y = 2x - 2

4x - (2x -2) = 10

4x - 2x + 2 = 10

2x = 8

x = 4

4(4) - y = 10

-y = -6

y = 6

So x = 4 y= 6

Hope this helps!
Brainliest and a like is much appreciated!
6 0
2 years ago
Read 2 more answers
Match the parabolas represented by the equations with their vertices. y = x2 + 6x + 8 y = 2x2 + 16x + 28 y = -x2 + 5x + 14 y = -
GaryK [48]

Consider all parabolas:

1.

y = x^2 + 6x + 8,\\y=x^2+6x+9-9+8,\\y=(x^2+6x+9)-1,\\y=(x+3)^2-1.

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.

2.

y = 2x^2 + 16x + 28=2(x^2+8x+14),\\y=2(x^2+8x+16-16+14),\\y=2((x^2+8x+16)-16+14),\\y=2((x+4)^2-2)=2(x+4)^2-4.

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.

3.

y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.

4.

y =-x^2 + 7x + 7=-(x^2-7x-7),\\y=-(x^2-7x+\dfrac{49}{4}-\dfrac{49}{4}-7),\\y=-((x^2-7x+\dfrac{49}{4})-\dfrac{49}{4}-7),\\y=-((x-\dfrac{7}{2})^2-\dfrac{77}{4})=-(x-\dfrac{7}{2})^2+\dfrac{77}{4}.

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.

5.

y =2x^2 + 7x +5=2(x^2+\dfrac{7}{2}x+\dfrac{5}{2}),\\y=2(x^2+\dfrac{7}{2}x+\dfrac{49}{16}-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x^2+\dfrac{7}{2}x+\dfrac{49}{16})-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x+\dfrac{7}{4})^2-\dfrac{9}{16})=2(x+\dfrac{7}{4})^2-\dfrac{9}{8}.

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.

6.

y =-2x^2 + 8x +5=-2(x^2-4x-\dfrac{5}{2}),\\y=-2(x^2-4x+4-4-\dfrac{5}{2}),\\y=-2((x^2-4x+4)-4-\dfrac{5}{2}),\\y=-2((x-2)^2-\dfrac{13}{2})=-2(x-2)^2+13.

When x=2, y=13, then the point (2,13) is vertex of this sixth parabola.

3 0
3 years ago
A section in a stained glass window is shaped like a trapezoid. The top base is 2 centimeters and the bottom base is 4.5 centime
Elza [17]

Answer:

2.8 cm

Step-by-step explanation:

The area of a trapezoid is calculated using the formula:

A=\frac{(B+b)h}{2}

where

B is the length of the major base

b is the length of the minor base

h is the height of the trapezoid

In this problem, the glass window has the shape of a trapezoid. We know that:

B = 2 cm is the length of the top base

b = 4.5 cm is the length of the bottom base

A=9.1 cm^2 is the area of the trapezoid

Solving for h, we can find the height of the stained glass window:

h=\frac{2A}{B+b}=\frac{2(9.1)}{2+4.5}=2.8 cm

8 0
3 years ago
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