2.85 as a mixed number
1 answer:
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Answer:
The probability that a randomly chosen child in 11th grade and play tennis is 9.6% ⇒ D
Step-by-step explanation:
- P(A) and P(B) = P(A) . P(B)
- P(A) or P(B) = P(A) + P(B)
The table represents the percentage of the students in each sport
→ The rows represent the grades level, the columns represent the sports
∵ The percentage of students in grade 11 = 40%
∴ The probability of choosing a child in grade 11th = = 0.40
∵ The percentage of students who playing tennis = 24%
∴ The probability of choosing a child who playing tennis = = 0.24
→ We need to find the probability of a randomly chosen child in
11th grade and playing tennis
∵ The probability of A and B is P(A) . P(B), where P(A) is the probability of
choosing a child in 11th grade and P(B) is the probability of choosing
a child playing tennis
∵ P(A) = 0.40 and P(B) = 0.24
∴ P(A) and P(B) = 0.40 × 0.24
∴ P(A) and P(B) = 0.096
→ Change it to a percentage by multiplying it by 100
∴ P(A) and P(B) = 0.096 × 100%
∴ P(A) and P(B) = 9.6%
∴ The probability that a randomly chosen child in 11th grade and
play tennis is 9.6%