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-Dominant- [34]
3 years ago
7

In ΔQRS, the measure of ∠S=90°, QR = 71 feet, and SQ = 50 feet. Find the measure of ∠R to the nearest degree.

Mathematics
2 answers:
lesya692 [45]3 years ago
6 0

Answer:44.767=45

Step-by-step explanation:

sinR=

71

50

​

R=\sin^{-1}(\frac{50}{71})

R=sin

−1

(

71

50

​

)

R=44.767\approx 45^{\circ}

R=44.767≈45

∘

Sveta_85 [38]3 years ago
4 0

Answer:

45

Step-by-step explanation:

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