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nika2105 [10]
2 years ago
9

Question 8 of 10 If f(x)=2x² +5√√(x-2), complete the following s f(3) =

Mathematics
1 answer:
nika2105 [10]2 years ago
7 0

Answer:

use air math it will tell u the answer

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Write the equation of the line that has undefined slope and passes through the point(-5,9)
jasenka [17]

Write the equation of the circle with center (3, 2) and radius r = 7. Use the ^ key for the exponents. Write your answer as the example: (x - 4)^2+(y+8)^2=25


6 0
3 years ago
Use the distrubutive property to simply 2(-5-7j)
prisoha [69]

<u>Answer:</u>

2(-5 - 7j) = -10 - 14j

<u>Step-by-step explanation:</u>

Using the distributive property means that we have to multiply both -5 and -7j by 2:

2(-5 - 7j)

⇒ 2 × -5  +  2 × -7j

⇒ -10 - 14j

8 0
2 years ago
I need the work and the answers
serg [7]

Answer:

.

Step-by-step explanation:

4 0
3 years ago
From a pool of 12 candidates, the offices of president, vice-president, secretary, and treasurer will be filled. In how many dif
Romashka [77]

Answer:

11,880 different ways.

Step-by-step explanation:

We have been given that from a pool of 12 candidates, the offices of president, vice-president, secretary, and treasurer will be filled. We are asked to find the number of ways in which the offices can be filled.

We will use permutations for solve our given problem.

^nP_r=\frac{n!}{(n-r)!}, where,

n = Number of total items,  

r = Items being chosen at a time.        

For our given scenario n=12 and r=4.

^{12}P_4=\frac{12!}{(12-4)!}

^{12}P_4=\frac{12!}{8!}

^{12}P_4=\frac{12*11*10*9*8!}{8!}

^{12}P_4=12*11*10*9

^{12}P_4=11,880

Therefore, offices can be filled in 11,880 different ways.

     

   

3 0
3 years ago
What are the ordered pairs of the
9966 [12]

Start by writing the system down, I will use y to represent f(x)

y=x^2-5x+3\wedge y=-3

Substitute the fact that y=-3 into the first equation to get,

-3=x^2-5x+3

Simplify into a quadratic form (ax^2+bx+c=0),

x^2-5x+6=0

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

x^2+x(m+n)+mn=0

which then must factor into

(x+m)(x+n)=0

And the solutions will be m,n.

Clearly for small coefficients like ours 5,6, this is very easy to figure out. To get 5 and 6 we simply say that m=3, n=2.

This fits the definition as 5=3+2 and 6=2\cdot3.

So as mentioned, solutions will equal to m=3, n=2 but these are just x-values in the solution pairs of a form (x,y).

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are (2,0) and (3,0).

Hope this helps :)

5 0
3 years ago
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