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RSB [31]
3 years ago
11

Select the correct answer. A company that packages cold cuts needs to transport the packaged meat to the supermarket. It will co

st $1,200 to rent a truck, and it will cost an additional $100 for every 50 pounds transported. Which equation represents the transport cost for every 50 pounds of cold cuts transported? A. y = 1,200 − 100x B. y = 1,200 + 100x C.y = 1,200x + 100 D. y = 100x − 1,200
Mathematics
2 answers:
qaws [65]3 years ago
4 0
The required equation is y = 1,200 + 100x
Sauron [17]3 years ago
4 0

y=1200+100x thats the correct answer

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What is the rational number equivalent to 3 point 12 with a bar over 12?
slamgirl [31]
\frac{12}{100}=0.12

To get the 0.12 to repeat, the trick is to subtract 1 from the denominator

\frac{12}{99}=0.12121212...

Then reduce the fraction.

\frac{12}{99}={4}{33}

now add the 3 to get

3.12121212.... = 3\frac{4}{33}
8 0
3 years ago
Read 2 more answers
How can you write the expression with rationalized denominator? 2+sqrt3(3)/sqrt3(6)
joja [24]
So we have a 6 at the bottom, and the root is 3, so hmm how to take it out, simple enough, just let's get something to make the 6 a 6³, so it comes out of the root

so 

\bf \cfrac{2+\sqrt[3]{3}}{\sqrt[3]{6}}\cdot \cfrac{\sqrt[3]{6^2}}{\sqrt[3]{6^2}}\implies \cfrac{(2+\sqrt[3]{3})(\sqrt[3]{6^2})}{(\sqrt[3]{6})(\sqrt[3]{6^2})}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3}\cdot \sqrt[3]{36}}{\sqrt[3]{6^3}}
\\\\\\
\cfrac{2\sqrt[3]{36}+\sqrt[3]{3\cdot 36}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{108}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3^3\cdot 4}}{6}
\\\\\\
\cfrac{2\sqrt[3]{36}+3\sqrt[3]{ 4}}{6}
8 0
3 years ago
What is the measure of angle x? m<x = ?
Ainat [17]
Hey there! :)

The total measure for triangles is 180°

You already know 2 angles. Add both angles and subtract from 180 to find x

37 + 82 = 119

180 - 119 = 61

m∠x = 61°

Hope this helps :)
3 0
3 years ago
Help please 4, 5, 6.......
Assoli18 [71]

4.  Supplementary angles together make a straight line (two right angles).  So BOE is supplementary to BOC

Answer: ∠BOE

5. Distance and midpoint between (4,-2), (6,8)

d = \sqrt{ (6-4)^2 + (8 - -2)^2} = \sqrt{2^2+10^2}=\sqrt{104}=2 \sqrt{26}

midpoint

\left(\dfrac{4 + 6}{2}, \dfrac{-2 + 8}{2} \right) = (5, 3)

Answer: distance 2√26, midpoint  (5, 3)

6.That's a rectangle oriented parallel to the axes, width parallel to the x axis of 7 - -3 = 10 and length along y of  1 - - 4 = 5, so an area of 10(5)=50

Answer: 50

5 0
3 years ago
Identify the domain of this relation. {(7,9), (4,6), (8, -10), (5, -7)}
IrinaK [193]
The domain is 7,4,8,5
3 0
3 years ago
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