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Olin [163]
3 years ago
13

How do you solve simple right triangles

Mathematics
1 answer:
jasenka [17]3 years ago
7 0
You can solve by using the pythagorean theorem. If you are given a right triangle, you should have two sides given, and one side missing. The diagonal side is called the hypotnuse, and it's the only side that is important with keeping to the same variable. The pythagorean theorem is: 
a²+b²=c². C is ALWAYS the hypotnuse.
If you are given one leg of the triangle and the hypotnuse, you can plug the leg into EITHER a or b and the hypotnuse in ONLY c. Then you can solve for the other variable. If you are given both legs and asked to find the hypotnuse, you can plug both legs into a and b and then solve for C. Remember that each variable is squared, so if you are solving for C or another side, you need to take the square root to get the variable alone. 
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<span>There are 4 long rows and 5 short rows in the theater. x represents the number of chairs in each long row and y represents the number of chairs in each short row.

So, total number of chairs in 4 long rows= 4x
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Total number of chairs in the theater on a normal day = 4x + 5y

When 2 chairs are added to each long row, the number of chairs will change to (x+2).
So, total number of chairs in 4 long rows will be = 4(x+2)

When 3 chairs are added to each short row, the number of chairs will change to (y+3)
So, total number of chairs in 5 short rows will be = 5(y+3)

Thus, total number of chairs in the theater in rush day = 4(x+2) + 5(y+3)
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Thus we can say the number of chairs increase by 23 as compared to a normal day.
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