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3 years ago

How do you solve simple right triangles

1 answer:

7 0

You can solve by using the pythagorean theorem. If you are given a right triangle, you should have two sides given, and one side missing. The diagonal side is called the hypotnuse, and it's the only side that is important with keeping to the same variable. The pythagorean theorem is:
a²+b²=c². C is ALWAYS the hypotnuse.
If you are given one leg of the triangle and the hypotnuse, you can plug the leg into EITHER a or b and the hypotnuse in ONLY c. Then you can solve for the other variable. If you are given both legs and asked to find the hypotnuse, you can plug both legs into a and b and then solve for C. Remember that each variable is squared, so if you are solving for C or another side, you need to take the square root to get the variable alone.

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a car starts from rest and travels for 5.0s with a uniform acceleration of 1.5 m/s^2. what is the final velocity of the car? how

AfilCa [17]

V = u + at
u = 0
v = 0 + 1.5*5
v = 7.5 m/s
final velocity is 7.5 m/s

s = ut + 0.5at^2
s = 0 + (0.5*1.5*5^2)
s = (0.5*1.5*25)
s = 18.75 m
total travel distance is 18.75 m.

5 0

3 years ago

The hypotenuse of a right triangle is 10cm long. The longer leg is 2cm longer than the shorter leg. Find the side lengths of the

Crazy boy [7]

We need Pythagoras theorem here
a^2+b^2 = c^2
a, b = legs of a right-triangle
c = length of hypotenuse

Let S=shorter leg, in cm, then longer leg=S+2 cm
use Pythagoras theorem
S^2+(S+2)^2 = (10 cm)^2
expand (S+2)^2
S^2 + S^2+4S+4 = 100 cm^2 [collect terms and isolate]
2S^2+4S = 100-4 = 96 cm^2
simplify and form standard form of quadratic
S^2+2S-48=0
Solve by factoring
(S+8)(S-6) = 0 means (S+8)=0, S=-8
or (S-6)=0, S=6
Reject nengative root, so
Shorter leg = 6 cm
Longer leg = 6+2 cm = 8 cm
Hypotenuse (given) = 10 cm

5 0

2 years ago

Solve the following system of equations by substitution

WITCHER [35]

Answer:

(-1, 1)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Coordinates (x, y)
Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

y = 2x + 3

y = x + 2

Step 2: Solve for x

Substitution

Substitute in y: 2x + 3 = x + 2
[Subtraction Property of Equality] Subtract x on both sides: x + 3 = 2
[Subtraction Property of Equality] Subtract 3 on both sides: x = -1

Step 3: Solve for y

Substitute in x [Original Equation]: y = -1 + 2
Add: y = 1

3 0

3 years ago

Read 2 more answers

What is the greatest factor of 60 and 75

Radda [10]

The greatest factor of 60 and 75 is 15.

Reasoning: I found the factors and prime factorization of 60 and 75. The biggest common factor number is the GCF number. So the greatest common factor 60 and 75 is 15.

8 0

3 years ago

Read 2 more answers

I need the answers to this

adoni [48]

It would be -140=x... to get this you would multiply x over 14 by 14... since you did it to one side then you have to do it to the other

6 0

3 years ago

Read 2 more answers