Evaluate -3w -2p for w=7 and p= -3
1 answer:
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Answer: Choice A)
This is the same as writing 14^3
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Explanation:
Since all the sides are 14 feet long, we can basically say length = width = height = 14.
Or put another way:
- length = 14
- width = 14
- height = 14
The volume of the cube is length*width*height = 14*14*14 = 14^3 = 2744 cubic feet.
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The term 14^3 has a base of 14 and exponent of 3.
The base is what we multiply out while the exponent tells us how many copies of the base to multiply. In this problem, we have 3 copies of 14 being multiplied. So that's why 14^3 = 14*14*14
If you were to say something like 3^14, then you would have 14 copies of 3 multiplied out, which is a much larger value. So we'll cross choice B off the list.
Choice C isn't correct either since again we're using exponents and not multiplication to tie together the 14 and 3.
Choice D would be correct if your teacher wanted it in expanded form, instead of exponent form.
Answer:
111011
Step-by-step explanation:
Following the binary rule we can find the base 2 presentation of the decimal number 59.
To find the binary equivalence of 59 we use the sum of powers of 2.
Now we take our number and find out what the binary number will by taking our largest number closest to the number first.
59 = 32
We chose the number 32 since 64 will be a larger value than 59.
We then check how much we have to add to 32 to get 59.
59 = 32 + 27
We then look for the closest number to 27 in our powers of 2.
59 = 32 + 16
Now we check again for how much we need left to get a total of 59.
59 = 32 + 16 + 11
Now we repeat the same process of finding which value in the powers of 2 are closest to the number.
59 = 32 + 16 + 8 + 3
59 = 32 + 16 + 8 + 2 + 1
Now since we already have a total of 59, our binary number will be all the numbers present will have a value of 1 and the numbers now used will have a number of 0.
32 16 8 4 2 1
This can also be represented as:
2^5 2^4 2^3 2^1 2^0
Now we have to include the numbers that we skipped to get the total binary number.
32 16 8 4 2 1
1 1 1 0 1 1
This can be represented as:
59 = 32 16 + 8 + 0 + 2 + 1
1 1 1 0 1 1