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2 years ago

Solve for x. Round your answer to the nearest tenth. 4.8 in 7.4 in

Mathematics

2 answers:

deff fn [24]2 years ago

7 0

Answer:

5.6

........................................................................

lina2011 [118]2 years ago

4 0

Answer:

x = 5.6

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2+b^2 = c^2

4.8 ^2 + x^2 = 7.4^2

23.04 +x^2 =54.76

Subtract 23.04 from each side

x^2 = 54.76 - 23.04

x^2 =31.72

Take the square root of each side

x =5.632051136

Rounding to the nearest tenth

x = 5.6

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The area of a rectangle is 20 square inches. If the length is 4 inches less than 6 times the width, then find the dimensions of

Tpy6a [65]

Step-by-step explanation:

Let the width=x

Length =6x-4

As we know that in a rectangle

${\boxed{\sf Area=LB}}$

Substitute the values

$\hookrightarrow\sf x (6x-4)=20$

$\hookrightarrow\sf 6x^2-4x=20$

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3 years ago

brenda and her bestfriend went on a vacation together. They both paid for a flight, and brenda had a fancy room for $150 per nig

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Answer:

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3 years ago

Is the dolphin deeper than point C or point E?

Pepsi [2]

Point E is correct answer

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3 years ago

The exam scores for 200 students are normally distributed with a mean of 72 and a standard deviation of 10. Which answer choice

Paha777 [63]

Using the normal distribution, it is found that there are 68 students with scores between 72 and 82.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

$\mu = 72, \sigma = 10$

The proportion of students with scores between 72 and 82 is the <u>p-value of Z when X = 82 subtracted by the p-value of Z when X = 72</u>.

X = 82:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{82 - 72}{10}$

Z = 1

Z = 1 has a p-value of 0.84.

X = 72:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{72 - 72}{10}$

Z = 0

Z = 0 has a p-value of 0.5.

0.84 - 0.5 = 0.34.

Out of 200 students, the number is given by:

0.34 x 200 = 68 students with scores between 72 and 82.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

6 0

2 years ago