This is a multiple choice question.

Mathematics

1 answer:

VikaD [51]3 years ago

8 0

Answer:

Both are correct

Step-by-step explanation:

A store is having a 20% off sale. Micheal says that he can find the sale price of an item that has a regular price of "p" by evaluating the expression 0.8"p". Susan says that she can find the sale price for the same item by evaluating the expression "p"-0.2"p"

Store is having 20% off sale. Discount is 20%

LEt the regular price is 'p'

The discount price is 20% of p that is 0.2p

Sale price is original price - discount price

that is p - 0.2p . So Suna is correct

p - 0.2 p = 1p- 0.2p = 0.8p

So Michel is also correct

Hence, Both are correct

You might be interested in

A standard NBA basketball has a radius of about 4.7 inches. What is the volume of an NBA basket ball? Use 3.14 for pi, and round

Finger [1]

Answer:

V≈434.89cu. in.

https://socratic.org/answers/407738

Step-by-step explanation: MRK ME BRAINLIeST PLZZZzz

the link is not fake just copy and paste it

8 0

3 years ago

Read 2 more answers

We need to optimize f(x, y, z) = x + 2y subject to the constraints g(x, y, z) = x + y + z = 8 and h(x, y, z) = y2 + z2 = 4. To f

Evgesh-ka [11]

The Lagrangian is

$L(x,y,z,\lambda,\mu)=x+2y+\lambda(x+y+z-8)+\mu(y^2+z^2-4)$

with critical points where the partial derivatives vanish:

$L_x=1+\lambda=0\implies\lambda=-1$

$L_y=2+\lambda+2\mu y=0\implies\mu=-\dfrac1{2y}$

$L_z=\lambda+2\mu z=0\implies\mu=\dfrac1{2z}$

$L_\lambda=x+y+z-8=0$

$L_\mu=y^2+z^2-4=0$

The second and third equations tell us $z=-y$ , so that in the last equation we find

$y^2+(-y)^2=2y^2=4\implies y=\pm\sqrt2\implies z=\mp\sqrt2$

and from the fourth equation we get

$x+y+z=x=8$

So we have two critical points, $(8,\sqrt2,-\sqrt2)$ and $(8,-\sqrt2,\sqrt2)$ , which give respective extreme values of $f(8,\sqrt2,-\sqrt2)=8+2\sqrt2$ (maximum) and $f(8,-\sqrt2,\sqrt2)=8-2\sqrt2$ (minimum).