Which equations would be related to x

Explain how to write a radical expression as an exponent?

Pie

Step-by-step explanation:

In order to rewrite an expression in radical form using exponents, we must consider the power of the root (is the radical the typical square root, cubed root, etc) and the value of any exponents contained in the radical.

Using this information, we will make the power of the radical the denominator of our exponent, and whatever exponent is contained in the radical will become the numerator.

Example:√(x³) = square root of x³ = x^(3/2)

Hopefully this is what you need!

7 0

2 years ago

EXERCISE

Olin [163]

Answer:

1)The probability that the ball drawn is not red is 6 /14

2)Probability of getting either a prime or a multiple of 3 is 7/10

3)Probability of drawing three balls without replacement such that all three are Same colour is 0.0747

Probability of drawing three balls without replacement such that all three are different colour is 0.5

Step-by-step explanation:

1) A ball is drawn randomly from a bag containing 8 red, 4 blue and 2 green identical balls. Find the probability that the ball drawn is not red.

No. of red balls = 8

No. of blue balls = 4

No. of green balls = 2

Total no. of balls = 8+4+2=14

P(Getting red bal)= $\frac{8}{14}$

P( ball drawn is not red) = $1 - \frac{8}{14}=\frac{6}{14}$

So,the probability that the ball drawn is not red is 6 /14

2)What is the probability that a number chosen at random from the integers between 1 and 10 inclusive is either a prime or a multiple of 3?

Numbers : 1 ,2,3,4,5,6,7,8,9,10

Prime numbers: 2,3,5,7 = 4

Multiple of 3 = 3,6,9 =3

So, Probability of getting prime number = $\frac{4}{10}$

Probability of getting multiple of 3 = $\frac{3}{10}$

So, Probability of getting either a prime or a multiple of 3= $\frac{4}{10}+\frac{3}{10}=\frac{7}{10}$

Hence Probability of getting either a prime or a multiple of 3 is 7/10

3)A bag contains four red balls, five blue balls and six green balls. Three balls are drawn from the bag at random without replacement. What is the probability that all three are:

The same colour

Different colour

No. of red balls = 4

No. of blue balls = 5

No. of green balls = 6

Total balls = 15

Case 1 :all three are Same colour

So, probability of drawing three balls without replacement such that all three are Same colour = $\frac{4}{15} \times \frac{3}{14} \times \frac{2}{13}+\frac{5}{15} \times \frac{4}{14} \times \frac{3}{13}+\frac{6}{15} \times \frac{5}{14} \times \frac{4}{13}=0.0747$

So, probability of drawing three balls without replacement such that all three are different colour = $\frac{4}{10} \times \frac{5}{9} \times \frac{6}{8}+\frac{5}{10} \times \frac{4}{9} \times \frac{6}{8}+\frac{6}{10} \times \frac{5}{9} \times \frac{4}{8}=0.5$

So,probability of drawing three balls without replacement such that all three are Same colour is 0.0747

So,probability of drawing three balls without replacement such that all three are different colour is 0.5

3 0

4 years ago

How do I get to -11 to -5

anzhelika [568]

Answer:

ADD 6

Step-by-step explanation:

-11 + 6= -5

5 0

4 years ago

Read 2 more answers

The expression (x^n) (x^5)^3 is equivalent to x^30. What is the value of n?

-BARSIC- [3]

Answer:

n = 15

Step-by-step explanation:

$(x^n) (x^5)^3 = x^{30} \\ \\ (x^n) x^{15 }= x^{30} \\ \\ {x}^{n + 15} = {x}^{30} \\ \\ n + 15 = 30 \\ \\ n = 30 - 15 \\ \\ n = 15$

4 0

2 years ago

What fractions in this list are less than 1/2? 3/6,7/15,4/9,5/8

Vedmedyk [2.9K]

All we need to do is to find a common denominator for both 1/2 and the other numbers individually:

1/2 = 3/6 (so 3/6 is not less than 1/2 - both numbers are equal)
1/2 = 15/30 and 7/15 = 14/30 (so 7/15 is less than 1/2)
1/2 = 9/18 and 4/9 = 8/18 (so 4/9 is less than 1/2)
1/2 = 4/8 (so 5/8 is not less - it's greater than 1/2)

Answer: From the list above only <u>7/15 and 4/9</u> are less than 1/2.

7 0

4 years ago

Which equations would be related to x - 7 = 38