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3 years ago

Please I need answers for these two asap! Please explain your answer I will mark brainliest!!!

Mathematics

2 answers:

grandymaker [24]3 years ago

5 0

Answer:

1.) Triangle ABC is congruent to triangle DCB

Step-by-step explanation:

For the first one, the first 3 steps proved that all 3 sides in the 2 triangles formed by the diagonal are congruent to each other, meaning triangle ABC is congruent to triangle DCB (I named it like that specifically because the way you name the triangles has to be the exact same way you named the other triangle).

For the second one, the congruency statement should be GL ≅ AD, because the HL congruence theorem states that if a hypotenuse and leg of one right triangle is congruent to the hypotenuse and leg of another right triangle, those triangles are congruent.

Ede4ka [16]3 years ago

4 0

Answer:

choice 4) Triangle ABC is congruent to triangle DCB because of the Side-Side-Side theorem

Step-by-step explanation:

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4 years ago

11. Name a pair of complementary angles in this figure.

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2 years ago

3. The path of an underground stream is given by the function y = 4x² +17x -32. Two

sineoko [7]

Answer:

The coordinate of the wells are

$(-4 -\sqrt[]{\frac{53}{2}}, 70+15\sqrt[]{\frac{53}{2}})$

$(-4 +\sqrt[]{\frac{53}{2}}, 70-15\sqrt[]{\frac{53}{2}})$

Step-by-step explanation:

The y coordinate of the stream is given by $y = 4x^2+17x-32$ . Also, the y coordinate of the houses are determined by y=-15x+10. We will assume that the houses are goint to be built on the exact position where we build the wells. We want to build the wells at the exat position in which both functions cross each other, so we have the following equation

$4x^2+17x-32 = -15x+10$

or equivalently

$4x^2+32x-42=0$ (by summing 15x and substracting 10 on both sides)

Dividing by 2 on both sides, we get

$2x^2+16x-21=0$

Recall that given the equation of the form $ax^2+bx+c=0$ the solutions are

$x = \frac{-b \pm \sqrt[]{b^2-4ac}}{2a}$

Taking a =2, b = 16 and c = -21, we get the solutions

$x_1 = -4 -\sqrt[]{\frac{53}{2}}$

$x_2 = -4 +\sqrt[]{\frac{53}{2}}$

If we replace this values in any of the equations, we get

$y_1 = 70+15\sqrt[]{\frac{53}{2}}$

$y_2 = 70-15\sqrt[]{\frac{53}{2}}$

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3 years ago

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ser-zykov [4K]

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4 years ago

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pishuonlain [190]

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8 0

3 years ago

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