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Tju [1.3M]
3 years ago
14

Consider the diagram.

Mathematics
1 answer:
Bingel [31]3 years ago
8 0
The answer you are looking for is C
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Which value could go in the blank cell so that the percentage of only children that
babunello [35]

Answer:

maybe B

I am not to my answer

8 0
3 years ago
I dont know this please any help would be nice
Leno4ka [110]
<h3>Answer:</h3>
  • C. Dependent
<h3>Explanation:</h3>

When events are independent the probability of one does not depend on the other.

Here the probability of liking peas overall is 39%, but the probability of liking peas if you're male is 42%. That is, the probabilities are not the same, so the events are dependent.

_____

<em>Comment on answer choices</em>

Selections B and C are both "Dependent," so are correct in that aspect. However, the "reason" given for B has a bogus number (54%) for males liking peas. We have no idea where that number came from. C has the correct reason, so is the appropriate selection.

4 0
3 years ago
2log5x+2logx5=5answer immediately
alexandr402 [8]

Answer:

Answer is below

Step-by-step explanation:

2\log _5\left(x\right)+10\log _{10}\left(x\right)

3 0
2 years ago
If an initial amount A0 of money is invested at an interest rate i compounded times a year, the value of the investment after t
seropon [69]

Answer:

Following are the solution to the given point:

Step-by-step explanation:

Please find the comp[lete question in the attached file.

Given:

\bold{ \lim_{n \to \ \infty} (1+ \frac{r}{n})^{nt} =e^{rt}}

In point 1:

\to y = (1+ \frac{r}{n})^{nt}

In point 2:

\to \ln (y)= nt \ln(1+  \frac{r}{n})

In point 3:

Its key thing to understand, which would be that you consider the limit n to\infty,  in which r and t were constants!  

=lim_{n \to \ \infty}  \ln (y) =  lim_{n \to \ \infty}  nt \ln(1+\frac{r}{n})\\\\=  lim_{n \to \ \infty} \frac{\ln(1+\frac{r}{n})}{\frac{1}{nt}}\\\\=  lim_{n \to \ \infty} \frac{\frac{-r}{\frac{n^2}{(1+\frac{r}{n})}}}{- \frac{1}{n^2t}}\\\\=  lim_{n \to \ \infty} \frac{\frac{rn^2t}{n^2}}{(1+\frac{r}{n})}\\\\=  lim_{n \to \ \infty} \frac{rt}{(1+\frac{r}{n})}\\\\= \frac{rt}{(1+\frac{r}{0})}\\\\=rt

In point 4:

\to \lim_{n \to \ \infty} = (1+\frac{r}{n})^{nt} and

\to \lim_{n \to \ \infty} = A_0e^{rt}

7 0
3 years ago
Someone please help me :((
Anon25 [30]

Answer: its the third one

Step-by-step explanation:

:)

3 0
3 years ago
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