3 years ago

\frac{h^{2}-1 }{h+3} when h=5Plz answer

Mathematics

1 answer:

Norma-Jean [14]3 years ago

4 0

Answer:

Step-by-step explanation:

$\frac{h^{2}-1 }{h+3}$

$\frac{5^{2} -1}{5+3}$

$\frac{25-1}{8}$

$\frac{24}{8}$

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2 years ago

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3 years ago

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