If tan(<span>θ) is negative, then </span><span>θ must be either in Q-II or else in Q-IV.
Fortunately, the question tells us that it's in Q-II.
If you draw a circle on the x- and y-axes, then draw a right triangle
in Q-II, then mark the legs 3 and -2, then the hypotenuse of the
triangle ... also the radius of the circle ... is √13 .
Look for the angle whose tangent is -3/2.
tangent = (opposite) / (adjacent)
So the side opp</span>osite is the 3 and the side adjacent is the -2.
For that same angle, cosine = (adjacent) / (hypotenuse) .
The adjacent side is still the -2, and the hypotenuse is √13 .
So the cosine of the same angle is
- 2 / √13 .
To rationalize the denominator (get that square root out of there),
multiply top and bottom by √13 . Then you have
(- 2 / √13) · (√13 / √13)
= - 2 √13 / 13 .
Answer:
6.966
Step-by-step explanation:
•Mark how many you have in the d.p
•If there is two or more add them up
•Multiply like normal given numbers
•Write where the decimal point is to be
Hope that helps
Answer:
It would be C i believe
Step-by-step explanation:
Perimeter = 2l + 2w
perimeter = 2(90) + 2(30)
perimeter= 180+60
perimeter= 240 ft
40^2 is how far apart the planes are after three hours travel
